Question

我的java类中有一个以下字符串值。

Nazar 1:46 PM Hello, I have few questions related to API Management 1:46 PM Sadhana has joined

我想根据其中提到的时间拆分它。它应该以这样的方式显示输出：每当有时间值到来时，它就会创建一个新的换行符。如下所示：

Nazar 1:46 PM Hello, I have few questions related to API Management. 1:46 PM Sadhana has joined

我怎样才能做到这一点。

Answer 1

您也可以使用此正则表达式。

(?=\b(((11|12|10|(0[1-9]{1})):)|[\d]:)[0-5][0-9](\s)?(?i)(am|pm))

Descritpion：

它应与hh:mm AM/PM和h:mm AM/PM匹配。

hh    -> hours 01-09 or 10,11,12 or 1-9
mm    -> minutes 00-59
AM/PM -> case insensitive

用法：

 String text = "Nazar 11:46 PM Hello, I have few questions related to API Management 10:46 PM "
            + "Sadhana has joined 06:35 AM its early 6:50 PM and late";

    String texts[] = text.split("(?=\\b(((11|12|10|(0[1-9]{1})):)|[\\d]:)[0-5][0-9](\\s)?(?i)(am|pm))");  

    for(String s : texts){
        System.out.println(s);
    }

输出：

Nazar 
11:46 PM Hello, I have few questions related to API Management 
10:46 PM Sadhana has joined 
06:35 AM its early 
6:50 PM and late

Answer 2

您可以尝试这样的事情：

str.split("(?=\\d{1,2}:\\d{1,2} (AM|PM))");

Answer 3

您可以使用此正则表达式进行拆分：

<?php

$xml = $argv[1];

$dom = new DOMDocument();

// Initial block (must before load xml string)
$dom->preserveWhiteSpace = false;
$dom->formatOutput = true;
// End initial block

$dom->loadXML($xml);
$out = $dom->saveXML();

print_R($out);

在前瞻模式的任意一侧使用字边界 String[] arr = str.split("(?=(?<!\\d:)\b\\d{1,2}:\\d{1,2}(?::\\d{1,2})? [AP]M\b)\\s*");非常重要：

RegEx Demo

Answer 4

这个正则表达式应该创建你想要的输出。

String s = "Nazar 1:46 PM Hello, I have few questions related to API Management 10:46 PM Sadhana has joined";
String s1[] = s.split("(\\s)(?=([01]?\\d:[0-6]?\\d\\s?([Aa]|[Pp])[Mm]))");
for (String s2 : s1) {
    System.out.println(s2);
}

Answer 5

Java有一个名为Matcher的类，您可以使用它来查找给定模式的出现次数。

此问题在链接中有合适的解决方案：Get the index of a pattern in a string using regex

如何在日期格式上拆分字符串

5 个答案: