我是新来的。我将不胜感激。最后一行代码不起作用。不知道如何解决。我知道第二个“ then”必须返回resolve(),但如何实现
let getNumber = new Promise((resolve) => {
//API
EthereumNote.getAmountOfMyNotes(function(error, result) {
if (!error) {
let AmountOfMyNotes = Number(result)
resolve(AmountOfMyNotes)
console.log(result)
} else
console.error(error)
})
}).then(result => {
return new Promise((resolve) => {
for (let i = 0, p = Promise.resolve(); i < result; i++) {
p = p.then(_ => new Promise(resolve => {
//API
EthereumNote.getMyNote(i, function(error, result) {
if (!error) {
let text = String(result[0])
let noteID = Number(result[1])
console.log(text)
console.log(noteID)
resolve()
} else
console.error(error)
})
}));
}
})
}).then(() => console.log('Hi!')) // this one doesn't work
答案 0 :(得分:1)
避免使用Promise
constructor antipattern!可以用new Promise
来包装EthereumNote.getMyNote
,也不能用循环来包装。您永远不会resolve()
那个外部承诺。
相反,只需返回您在p
中创建的承诺链即可:
let getNumber = new Promise((resolve) => {
//API
EthereumNote.getAmountOfMyNotes(function(error, result) {
if (error) reject(error);
else resolve(Number(result));
})
}).then(amountOfMyNotes => {
console.log(amountOfMyNotes);
var p = Promise.resolve();
for (let i = 0; i < amountOfMyNotes; i++) {
p = p.then(_ => new Promise((resolve, reject) => {
//API
EthereumNote.getMyNote(i, function(error, result) {
if (error) reject(error);
else resolve(result);
});
})).then(result => {
let text = String(result[0])
let noteID = Number(result[1])
console.log(text)
console.log(noteID))
});
}
return p;
}).then(() => {
console.log('Hi!'); // this one now works
}, err => {
console.error(err);
});