Txt预测模型数值表达式警告

时间:2019-02-24 20:13:27

标签: r prediction n-gram natural-language-processing

我有三个由不同ngram计数(Uni,Bi,Tri)创建的数据帧,每个数据帧包含分隔的ngram,频率计数(n),并使用平滑度增加了概率。

我编写了三个函数来浏览表并根据输入字符串返回最高可能的单词。并束缚了他们

##Prediction Model
trigramwords <- function(FirstWord, SecondWord, n = 5 , allow.cartesian =TRUE) {
probword <- trigramtable[.(FirstWord, SecondWord), allow.cartesian = TRUE][order(-Prob)]
if(any(is.na(probword)))
return(bigramwords(SecondWord, n))
if(nrow(probword) > n)
return(probword[1:n, ThirdWord])
count <-nrow(probword)
bgramwords <- bigramtable(SecondWord, n)[1:(n - count)]
return(c(probword[, ThirdWord], bgramwords))
}


bigramwords <- function(FirstWord, n = 5 , allow.cartesian = TRUE){
probword <- bigramtable[FirstWord][order(-Prob)]
if(any(is.na(probword)))
return(Unigramword(n))
if (nrow(probword) > n)
return(probword[1:n, SecondWord])
count <- nrow(probword)
word1 <- Unigramword(n)[1:(n - count)]
return(c(probword[, SecondWord], word1))
}

##Back off Model
Unigramword <- function(n = 5, allow.cartesian = TRUE){
return(sample(UnigramTable[, FirstWord], size = n))
}

## Bind Functions
predictword <- function(str) {
require(quanteda)
tokens <- tokens(x = char_tolower(str))
tokens <- char_wordstem(rev(rev(tokens[[1]])[1:2]), language = "english")

 words <- trigramwords(tokens[1], tokens[2], 5)
 chain_1 <- paste(tokens[1], tokens[2], words[1], sep = " ")

 print(words[1])
}

但是,我收到以下警告消息,并且输出始终是相同的单词。如果我仅使用bigramwords函数,则可以正常工作,但是在添加trigram函数时,会收到警告消息。我相信这是因为1:n定义不正确。

Warning message:
In 1:n : numerical expression has 5718534 elements: only the first used

0 个答案:

没有答案