Question

编辑我知道了：）它当然不是最优化的，但是可以工作：

$db = json_decode( file_get_contents( $location ), true );
$users = $db['users'];
$scoreTeam1 = 0;
$scoreTeam2 = 0;
$scoreTeam3 = 0;
$scoreTeam4 = 0;

foreach ($users as $user) {
    $team = $user['team'];
    $userScore = $user['userScore'];

    switch ($team) {
        case 1:
            $scoreTeam1 = $scoreTeam1 + $userScore;
            break;
        case 2:
            $scoreTeam2 = $scoreTeam2 + $userScore;
            break;
        case 3:
            $scoreTeam3 = $scoreTeam3 + $userScore;
            break;
        case 4:
            $scoreTeam4 = $scoreTeam4 + $userScore;
            break;
    }
}

最初的问题我想从以下json文件在php中创建团队排名：

"users": {
    "uniqueID": {
        "team": 1,
        "userScore": 2500,
    }, "uniqueID": {
        "team": 2,
        "userScore": 1235,
    }, "uniqueID": {
        "team": 3,
        "userScore": 6582,
    }, "uniqueID": {
        "team": 4,
        "userScore": 1200,
    }, "uniqueID": {
        "team": 1,
        "userScore": 9875,
    }, "uniqueID": {
        "team": 2,
        "userScore": 500,
    }, "uniqueID": {
        "team": 3,
        "userScore": 12,
    }, "uniqueID": {
        "team": 4,
        "userScore": 695,
    }, "uniqueID": {
        "team": 1,
        "userScore": 332,
    }, etc.
}

我有4个团队，我想我需要创建4个变量：

$scoreTeam1
$scoreTeam2
$scoreTeam3
$scoreTeam4

您能帮我翻译一下吗：对于每个唯一ID 如果团队== 1得分团队1 + =用户得分，否则，如果team == 2 scoreTeam2 + = userScore，等等...

任何帮助都非常值得欢迎：）最好的问候。

Answer 1

您可以使用array_reduce函数来实现所需的目标：

$result = array_reduce($db['users'], function($carry, $team){
   if (isset($carry[$team['team']]) ) {
       $carry[$team['team']] = $carry[$team['team']] + $team['userScore'];
   } else {
       $carry[$team['team']] = $team['userScore'];
   }    
   return $carry;
});

唯一的ID用户团队排名php / json

1 个答案: