Question

这个新代码适合我，但不完全，现在的问题是所有用户都有相同的排名，都有1°

 <?php
 mysql_connect($mysql_host, $mysql_user, $mysql_pass) or die(mysql_error());
mysql_select_db($mysql_db) or die(mysql_error());
$sql = "SELECT ID, Name, username, Wins, Loses, Draws, (Wins + Loses) AS points FROM users WHERE username='$_GET[user]' ORDER BY points DESC";
$result = mysql_query($sql) or die(mysql_error());
if( !$result ){
  echo 'SQL Query Failed';
 }else{
  $rank = 0;
$last_score = false;
$rows = 0;
while( $row = mysql_fetch_array( $result ) ){
$rows++;
if( $last_score!= $row['Wins'] ){
  $last_score = $row['Wins'];
  $rank = $rows;
}
echo "rank ".$rank." is ".$row['Name']." with point ".$row['Wins']."";
}
}
?>

我需要

Example:
 ID username Wins Loses
 1    demo    12   12   RANKIG= 1°
 2    demo2   1    3    RANKIG= 2°

Answer 1

尝试将您的查询视为：

<link href="https://cdnjs.cloudflare.com/ajax/libs/c3/0.4.10/c3.min.css" rel="stylesheet" />
    <script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.5.6/d3.min.js"></script>
    <script src="https://cdnjs.cloudflare.com/ajax/libs/c3/0.4.10/c3.min.js"></script>

<div id="ageChart"></div>

用户排名系统

1 个答案: