我要使用此查询在“ MakinelerVeParcalar”表上进行更新;
UPDATE MakinelerVeParcalar SET Durum = 'Montaj' WHERE ID = 161
我得到了这个错误;
消息512,级别16,状态1,过程trgSureUpdate,第31行[批处理开始第0行] 子查询返回的值超过1。当子查询遵循=,!=,<,<=,>,> =或将子查询用作表达式时,不允许这样做。
我的trgSureUpdate(Trigger)
ALTER TRIGGER [dbo].[trgSureUpdate]
ON [dbo].[MakinelerVeParcalar]
AFTER UPDATE
AS
BEGIN
DECLARE @count INT
DECLARE @idinserted INT
DECLARE @duruminserted VARCHAR(50)
DECLARE @max INT
DECLARE @iddeleted INT
DECLARE @durumdeleted VARCHAR(50)
DECLARE @datediff INT
DECLARE @durumbilgisi varchar(50)
DECLARE @sureinserted INT
DECLARE @suredeleted INT
DECLARE @diffdate INT
SELECT @idinserted = ID from inserted <-- Line 31
SELECT @duruminserted = Durum from inserted
SELECT @iddeleted = ID from deleted
SELECT @durumdeleted = Durum from deleted
SET @count = (SELECT count(*) FROM Sure WHERE ID = @idinserted and Asama = @duruminserted)
SET @max = (SELECT max(SiraNo) FROM Sure WHERE ID = @idinserted)
SET @durumbilgisi = (SELECT DurumBilgisi FROM DurumBilgisi WHERE ID = @idinserted)
SET @sureinserted = (SELECT Sure FROM Sure WHERE ID = @idinserted and Asama = @duruminserted)
SET @suredeleted = (SELECT Sure FROM Sure WHERE ID = @iddeleted and Asama = @durumdeleted)
IF @duruminserted != @durumdeleted
BEGIN
IF @durumbilgisi != 'Bitti'
BEGIN
UPDATE Sure Set Cikis = GETDATE() WHERE Asama = @durumdeleted and ID = @idinserted and SiraNo = @max
SET @diffdate = DATEDIFF (SECOND,(SELECT Giris FROM Sure WHERE ID = @idinserted and SiraNo = @max),(SELECT Cikis FROM Sure WHERE ID = @idinserted and SiraNo = @max))
UPDATE Sure SET Sure = (@diffdate) WHERE ID = @idinserted and SiraNo = @max
END
INSERT INTO Sure (ID,Asama,Giris,Cikis,Sure,SiraNo) VALUES(@idinserted,@duruminserted,GETDATE(),NULL,0,(@max+1))
UPDATE DurumBilgisi SET DurumBilgisi = 'Devam Ediyor' WHERE ID = @idinserted
END
END
答案 0 :(得分:0)
我认为您可能对行号感到困惑。您已将此标记为第31行,但即使在INSERTED上有多行,它也不会引发错误:
SELECT @idinserted = ID from inserted
但是,如果SELECT返回多于1行,这将引发错误:
SET @durumbilgisi = (SELECT DurumBilgisi FROM DurumBilgisi WHERE ID = @idinserted)
select @var = col from table
语法和set @var = (select col from table)
语法之间存在差异。您需要检查SET
查询。