Question

我需要更新tableA的总计字段与查询的结果 按DATE，RNAME

从SALES组中选择SUM（amt）

我试过这个

更新表设置总计=（从DATE，RNAME中选择SALES组的总和（billamt）

显示错误子查询返回的值超过1。当子查询遵循=，！=，＆lt;，＆lt; =，＆gt;，＆gt; =或子查询用作表达式时，不允许这样做。

Answer 1

查询：

select sum(billamt) from SALES group by DATE,RNAME

返回sum的{{1}}，按billamt分组。

如果您有多个DATE,RNAME或DATE个唯一值，则返回的值是一个表（而不是一个字段）。

您可以单独运行此查询并检查返回的值。

如错误所述，您不能为字段设置多个值。

Answer 2

尝试类似：

update A
set Total = B.Total
From tableA  A
Inner Join (select DATE,RNAME,sum(billamt) Total from SALES group by DATE,RNAME) B
On A.Date = B.Date and A.RName = B.RNAme

Answer 3

由于表结构在上述问题中不明确，我假设tableA有列Total，Date和RName

update tableA set tableA.total = 
a.total from (select SUM(amt) as total, date, rname from SALES group by DATE,RNAME) as a
where a.date = tableA.date and tableA.rname = a.rname

- 编辑“销售表中Rname可以为空的情况”使用

update tableA set tableA.total = a.total
from (select SUM(amt) as total, date, rname from #t1 group by DATE,RNAME) as a
where a.date = tableA.date and tableA.rname = a.rname
OR (a.date = tableA.date AND tableA.rname IS NULL and a.rname IS NULL)

- 进一步阐述

CREATE TABLE #t1 (amt decimal(18,2), [date] date, rname varchar(50))
INSERT INTO #t1
SELECT 1.9, GETDATE() - 1, NULL
UNION ALL
SELECT 1.9, GETDATE() - 1, NULL
UNION ALL
SELECT 8.9, GETDATE() - 1, NULL
UNION ALL
SELECT 8.9, GETDATE(), NULL
UNION ALL
SELECT 2.9, GETDATE() - 1, 'N1'
UNION ALL
SELECT 2.8, GETDATE() - 1, 'N1'

CREATE TABLE #t2 (total decimal(18,2), [date] date, rname varchar(50))
INSERT INTO #t2
SELECT 0, GETDATE() - 1, NULL
UNION ALL
SELECT 0, GETDATE() - 1, 'N1'

update #t2 set #t2.total = a.total
from (select SUM(amt) as total, date, rname from #t1 group by DATE,RNAME) as a
where a.date = #t2.date and #t2.rname = a.rname
OR (a.date = #t2.date AND #t2.rname IS NULL and a.rname IS NULL)


SELECT * FROM #t2

我希望现在明白

子查询返回的值超过1。当子查询跟随=，！=或子查询用作表达式时，不允许这样做

3 个答案: