Question

我正在使用Alloy（钛SDK：7.5.0，iOS SDK：12.1，Xcode版本：10.1）和Axway Appcelerator开发iOS应用。我想在Titanium.Media.VideoPlayer中可视化.mp4文件，该文件位于运行Flask和flask-socketio的工作站中。由于Titanium的VideoPlayer想要文件的远程URL来播放它，所以我用Flask的脚本编写：

@app.route('/<vid_name>')
def serve_video(vid_name):
    vid_path = os.path.join('/home/myFolder', vid_name)
    resp = make_response(send_file(vid_path, 'video/mp4'))
    resp.headers['Content-Disposition'] = 'inline'
    return resp

但是当VideoPlayer尝试使用其URL访问.mp4文件时，我从Flask收到此错误：

IP - - [21/Feb/2019 17:10:58] "GET /myVid.mp4 HTTP/1.1" 200 -
----------------------------------------
Exception happened during processing of request from ('IP', 51600)

Traceback (most recent call last):
  File "/home/myUser/miniconda2/envs/T2/lib/python2.7/SocketServer.py", line 596, in process_request_thread
    self.finish_request(request, client_address)
  File "/home/myUser/miniconda2/envs/T2/lib/python2.7/SocketServer.py", line 331, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "/home/myUser/miniconda2/envs/T2/lib/python2.7/SocketServer.py", line 654, in __init__
    self.finish()
  File "/home/myUser/miniconda2/envs/T2/lib/python2.7/SocketServer.py", line 713, in finish
    self.wfile.close()
  File "/home/myUser/miniconda2/envs/T2/lib/python2.7/socket.py", line 283, in close
    self.flush()
  File "/home/myUser/miniconda2/envs/T2/lib/python2.7/socket.py", line 307, in flush
    self._sock.sendall(view[write_offset:write_offset+buffer_size])
error: [Errno 32] Broken pipe

我做错了什么？如何使用URL访问.mp4文件并在Titanium.Media.VideoPlayer中可视化？

如何在Titanium的VideoPlayer中可视化Flask服务器中的.mp4文件？

0 个答案: