带条件的SQL SUM组

Question

我有SQL Server表名tbInvoice看起来像这样：

我对结果的期望是这样的：

该想法是根据VENDOR对所有行进行分组，根据total_inv + total_1 + total_2来计算GRAND TOTAL。状态为0（status_inv，status_1，status_2）。

我做了类似的事情，但是没用：

SELECT DISTINCT vendor, 
 SUM(CASE WHEN total_inv = 0 AND total_1 = 0, and total_2 = 0 THEN (total_inv + total_1 + total_2)  
          WHEN total_inv = 0 AND total_1 = 0, and total_2 = 1 THEN (total_inv + total_1)  
          WHEN total_inv = 0 AND total_1 = 1, and total_2 = 0 THEN (total_inv + total_2)
          WHEN total_inv = 0 AND total_1 = 1, and total_2 = 1 THEN (total_inv)
          WHEN total_inv = 1 AND total_1 = 0, and total_2 = 0 THEN (total_1 + total_2)  
          WHEN total_inv = 1 AND total_1 = 0, and total_2 = 1 THEN (total_1)  
          WHEN total_inv = 1 AND total_1 = 1, and total_2 = 0 THEN (total_2)
          WHEN total_inv = 1 AND total_1 = 1, and total_2 = 1 THEN 0 END) GRAND TOTAL FROM tbInvoice GROUP BY vendor  

非常感谢您。

Answer 1

您在CASE表达式中混淆了状态和总计。而且，您使它变得比必要的更为复杂。您要在状态为0时总计：

SELECT
  vendor, 
  SUM(CASE WHEN status_inv = 0 THEN total_inv ELSE 0 END) +
      CASE WHEN status_1   = 0 THEN total_1   ELSE 0 END) +
      CASE WHEN status_2   = 0 THEN total_2   ELSE 0 END)) AS grand_total
FROM tbInvoice
GROUP BY vendor  
ORDER BY vendor;

没有任何数学技巧；-）

Answer 2

如您所愿，表达更简单：

SELECT vendor, 
       sum( total_inv + total_1 * status_1 + total_2 * status_2) GRAND TOTAL 
FROM tbInvoice 
GROUP BY vendor

说明

在某些情况下（状态为0时），您不想将值聚合为总计；在其他情况下（状态为1时），您想要。然后，就像使用value * status一样容易，因为value * 0 = 0和value * 1 = value。

供您参考

在堆栈溢出screenshots are discouraged上，最好使用简单的复制粘贴文本。另外，我也恭喜您将您的工作发布到解决方案中。

已编辑

从OP评论看来，我应该切换status字段。

SELECT vendor, 
       sum(   total_inv * (1-status_inv) 
            + total_1   * (1-status_1) 
            + total_2   * (1-status_2)
          ) as GRAND TOTAL 
FROM tbInvoice 
GROUP BY vendor

Answer 3

希望这会有所帮助，在这里我得到所有总数的总和，然后乘以状态，然后减去总和，从而消除状态为1的总数，我选择此方法来保持此SQL代码ANSI，

    SELECT vendor, 
    SUM( total_inv + total_1  + total_2 -( total_inv*status_inv + total_1 * status_1 + total_2 * status_2)) as GRAND TOTAL 
    FROM tbInvoice 
    GROUP BY vendor