Question

我有一个关于clausule SUM的查询。我需要根据列的总和。

这可能吗？

有没有人让我看一个例子？

我的代码如下：

SELECT 
PL_MAT AS 'Código', 
RA_NOME AS 'Nome',
RJ_DESC AS 'Cargo',
SUM(PL_HORAS) AS 'Atrasos'
--SUM(PL_HORAS) AS 'Hora Extra' -- I need SUM this
FROM SPL020 
INNER JOIN SP9020 ON PL_PD = P9_CODIGO AND SP9020.D_E_L_E_T_ <> '*' AND SPL020.D_E_L_E_T_ <> '*'
INNER JOIN SRA020 ON RA_MAT = PL_MAT AND SRA020.D_E_L_E_T_ <> '*' AND RA_FILIAL = PL_FILIAL
INNER JOIN SRJ020 ON RJ_FUNCAO = RA_CODFUNC
WHERE PL_DATA BETWEEN '20120616' AND '20120715'
AND P9_CODIGO IN ('011','421','013','409')
--AND P9_CODIGO IN ('408','007','420','009','015','016','018') -- I need sum this 
AND RA_CODFUNC IN ('0408','1204','1233')--AUX COLETA C,MOTORISTA D,MOTORISTA CARRETEIRO
AND RA_SITFOLH NOT IN ('D','A')
AND PL_FILIAL = '05'
GROUP BY PL_MAT,RA_NOME,RA_ADMISSA,RA_CODFUNC,RJ_DESC,P9_DESC, PL_HORAS, P9_CODIGO
ORDER BY RA_NOME

Answer 1

这样做：

sum(case when p9_codigo in ('408','007','420','009','015','016','018') then pl_horas else 0 end) as 'Hora Extra'

如果你把AND P9_CODIGO IN（'011'，'421'，'013'，'409'）放在where子句中，那么上面的那些将不会被过滤。

所以你需要以不同的方式删除它们。

我想你需要它：

sum(case when p9_codigo in ('011','421','013','409') then PL_HORAS else 0 end) as 'Atrasos',
sum(case when p9_codigo in ('408','007','420','009','015','016','018') then pl_horas else 0 end) as 'Hora Extra'

并从where子句中删除过滤器。

Answer 2

知道了！谢谢大家

SELECT 
DISTINCT PL_MAT AS 'Código', 
RA_NOME AS 'Nome',
RJ_DESC AS 'Cargo',
SUM(CASE WHEN P9_CODIGO IN ('082','080','030','409') THEN PL_HORAS ELSE 0 END) AS 'Atrasos',
SUM(CASE WHEN P9_CODIGO IN ('408','007','420','009','015','016','018') THEN PL_HORAS ELSE 0 END) AS 'Hora extra'
--SUM(PL_HORAS) AS 'Hora Extra' -- I need SUM this
FROM SPL020 
INNER JOIN SP9020 ON PL_PD = P9_CODIGO AND SP9020.D_E_L_E_T_ <> '*' AND SPL020.D_E_L_E_T_ <> '*'
INNER JOIN SRA020 ON RA_MAT = PL_MAT AND SRA020.D_E_L_E_T_ <> '*' AND RA_FILIAL = PL_FILIAL
INNER JOIN SRJ020 ON RJ_FUNCAO = RA_CODFUNC
WHERE PL_DATA BETWEEN '20120616' AND '20120715'
--AND P9_CODIGO IN ('011','421','013','409')
--AND P9_CODIGO IN ('408','007','420','009','015','016','018') -- I need sum this 
AND RA_CODFUNC IN ('0408','1204','1233')--AUX COLETA C,MOTORISTA D,MOTORISTA CARRETEIRO
AND RA_SITFOLH NOT IN ('D','A')
AND PL_FILIAL = '05'
AND RA_MAT = '000007'
GROUP BY PL_MAT, RA_NOME, RJ_DESC

Answer 3

podéspromparesto：

选择nome，cargo，sum（Hora_Extra）作为Hora_Extra 从（选择 PL_MAT AS'Codigo'， RA_NOME AS'Nome'， RJ_DESC AS'Cargo'， SUM（PL_HORAS）AS'Atrasos'，

P9_CODIGO为'Codigo'

FROM SPL020

INNER JOIN SP9020 ON PL_PD = P9_CODIGO

AND SP9020.D_E_L_E_T_＆lt;＆gt; '*'

AND SPL020.D_E_L_E_T_＆lt;＆gt; '*'

INNER JOIN SRA020 ON RA_MAT = PL_MAT AND SRA020.D_E_L_E_T_＆lt;＆gt; '*'

AND RA_FILIAL = PL_FILIAL

INNER JOIN SRJ020 ON RJ_FUNCAO = RA_CODFUNC

在'20120616'和'20120715'之间的PL_DATA

AND P9_CODIGO IN（'011'，'421'，'013'，'409'）

AND RA_CODFUNC IN（'0408'，'1204'，'1233'）

AND RA_SITFOLH NOT IN（'D'，'A'）

AND PL_FILIAL ='05'

GROUP BY PL_MAT，RA_NOME，RA_ADMISSA，RA_CODFUNC，RJ_DESC，P9_DESC，PL_HORAS，P9_CODIGO

）作为kk

Codigo in（'408'，'007'，'420'，'009'，'015'，'016'，'018'）由nome命令

Unos提示：没有使用tildes（C“ó”digo）没有使用espacios en los campos（Horas Extras）

Saludos

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3 个答案: