Question

尽管我一直在寻找答案，但我对其中的任何一个都不太了解，所以我决定寻求直接帮助。

基本上，该程序应读取该数字的每个数字，然后正常记录下来。现在，这是一个“骨架”代码，因为我正在尝试进一步编程它的主要思想，但是我已经在错误中绊脚石了。

我使用的任何 switch 函数行均出现错误，但我不知道如何解决。我收到错误错误C2659：'='：用作左操作数

#include <iostream>
#include <string>

using namespace std;

int number, digit;
int i;
string word[4];

void lowering();
void units();
void tens();

int main()
{
i = 4;
    word[i];

cout << "Enter a number: ";
cin >> number;
cout << endl;

lowering();
units();
i--;
lowering();
tens();

for(int x = 4; x >=0; x--)
    cout << word[x];

system("pause");
return 0;
}

void lowering()
{
    digit = number % 10;
    number = number / 10;
}

void units()
{
    switch (digit)
    {
    case 1:
        word[i].append = " one"; break;
    case 2:
        word[i].append = " two"; break;
    case 3:
        word[i].append = " three"; break;
    case 4:
        word[i].append = " four"; break;
    case 5:
        word[i].append = " five"; break;
    case 6:
        word[i].append = " six"; break;
    case 7:
        word[i].append = " seven"; break;
    case 8:
        word[i].append = " eight"; break;
    case 9:
        word[i].append = " nine"; break;
    default:
        word[i].append = "";
    }

    word[i].append = " ";
}

void tens()
{
    switch (digit)
    {
    case 1:
        word[i].append = " ten"; break;
    case 2:
        word[i].append = " twenty "; break;
    case 3:
        word[i].append = " thirty "; break;
    case 4:
        word[i].append = " fourty"; break;
    case 5:
        word[i].append = " fifty"; break;
    case 6:
        word[i].append = " sixty"; break;
    case 7:
        word[i].append = " seventy"; break;
    case 8:
        word[i].append = " eighty"; break;
    case 9:
        word[i].append = " ninety"; break;
    default:
        word[i].append = "";
    }

    word[i].append = " ";
}

Answer 1

在切换情况下，您应该使用此命令：

void units()
{
    switch (digit)
    {
    case 1:
        word[i].append(" one"); break;
    case 2:
        word[i].append(" two"); break;
    case 3:
        word[i].append(" three"); break;
    case 4:
        word[i].append(" four"); break;
    case 5:
        word[i].append(" five"); break;
    case 6:
        word[i].append(" six"); break;
    case 7:
        word[i].append(" seven"); break;
    case 8:
        word[i].append(" eight"); break;
    case 9:
        word[i].append(" nine"); break;
    default:
        word[i].append("");
    }

    word[i].append(" ");
}

除了要提高代码质量外，还应该将break;放在新行中。

用作左操作数-我该怎么办？

1 个答案: