Question

试图弄清楚我的代码出了什么问题，请帮助我。该代码应该能够找出并打印出介于1到1000之间的理想数字以及数字的因数。我正在尝试调用perfect（number）函数，但始终弹出错误消息“需要Lvalue作为赋值的左操作数”。

#include <stdio.h>

int perfect(int number);

int main(void){

    printf("The perfect numbers between 1 and 1000 are\n:");

    for (int number = 1; number <=1000; number++){
        perfect(number);
        if (perfect(number) = 1){
            printf("%d is a perfect number; ", number);
            printf("It's factors are = ");
                for (int i = 1; i <= number; i++){ //might need to change i<number
                    if (number % i == 0){
                        printf("%d", i);
                    }
                }
        }
    }
    return 0;
}

int perfect(int number){

    int sum;

    for(int number = 1;number <= 1000; number++){
        sum = 0;

        for (int i = 1; i <= number/2; i++){
            if (number % i == 0){
                sum = sum + i;
            }
        }

        if (sum == number){
           return 1;
        }
        else {
            return 0;
        }
    }

}

Answer 1

在C语言（以及一堆借用其语法的其他语言）中，=是赋值运算符， not 是相等比较运算符。将if (perfect(number) = 1)更改为if (perfect(number) == 1)。

调用函数时需要左值作为赋值的左操作数

1 个答案: