Question

我有这样的输出：

output "esxi_gw_ip" {
  value = "${packet_device.esxi.network}"
}

结果是这样的：

       "outputs": {
                "esxi_gw_ip": {
                    "sensitive": false,
                    "type": "list",
                    "value": [
                        {
                            "address": "139.0.0.2",
                            "cidr": "29",
                            "family": "4",
                            "gateway": "139.0.0.1",
                            "public": "1"
                        },
                        {
                            "address": "blah",
                            "cidr": "127",
                            "family": "6",
                            "gateway": "blah",
                            "public": "1"
                        },
                        {
                            "address": "10.88.94.2",
                            "cidr": "29",
                            "family": "4",
                            "gateway": "10.88.94.1",
                            "public": "0"
                        }
                    ]
                }

我想从family = 4和public = 1获取网关...我该怎么做？我可以像这样从列表中获得第一个，然后在jq中使用类似local-exec的东西：

output "esxi_gw_ip" {
  value = "${packet_device.esxi.network[0]}"
}

但是这并不能保证它会一直0，而且我也在尝试以terraform与使用shell的方式自然地做到这一点……

Answer 1

解决了我的问题！如果有人感兴趣..这是我的操作方法....在main.tf中，我添加了以下内容：

data "template_file" "packet_gw_public" {
  count    = "${length(packet_device.esxi.network)}"
  template = "${lookup(packet_device.esxi.network[count.index], "public") == 1 && lookup(packet_device.esxi.network[count.index], "family") == "4" ? lookup(packet_device.esxi.network[count.index], "gateway") : "" }"
}

然后在output.tf中添加：

output "esxi_gw_ip" {
  value = "${element(compact(data.template_file.packet_gw_public.*.rendered),0)}"
}

terraform var输出以从地图列表中的地图元素中选取

1 个答案: