获取具有百分比的匹配字符串

时间:2019-02-18 08:47:24

标签: sql-server tsql sql-server-2008-r2

我有以下数据详细信息:

表1:Table1的大小在few records左右。

表2:Table2具有50 millions行。

要求:我需要将table1table2的任意字符串列匹配,例如将name列匹配到name,并获取百分比匹配(注释列可以是任何一个,可能是地址,也可以是单个单元格中具有多个单词的任何字符串列)。

样本数据:

create table table1(id int, name varchar(100), address varchar(200));

insert into table1 values(1,'Mario Speedwagon','H No 10 High Street USA');
insert into table1 values(2,'Petey Cruiser Jack','#1 Church Street UK');
insert into table1 values(3,'Anna B Sthesia','#101 No 1 B Block UAE');    
insert into table1 values(4,'Paul A Molive','Main Road 12th Cross H No 2 USA');
insert into table1 values(5,'Bob Frapples','H No 20 High Street USA');    

create table table2(name varchar(100), address varchar(200), email varchar(100));

insert into table2 values('Speedwagon Mario ','USA, H No 10 High Street','mario@gmail.com');
insert into table2 values('Cruiser Petey Jack','UK #1 Church Street','jack@gmail.com');
insert into table2 values('Sthesia Anna','UAE #101 No 1 B Block','Aanna@gmail.com');    
insert into table2 values('Molive Paul','USA Main Road 12th Cross H No 2','APaul@gmail.com');
insert into table2 values('Frapples Bob ','USA H No 20 High Street','BobF@gmail.com');  

预期结果

    tbl1_Name               tbl2_Name           Percentage  
--------------------------------------------------------
Mario Speedwagon        Speedwagon Mario    100
Petey Cruiser Jack      Cruiser Petey Jack  100
Anna B Sthesia          Sthesia Anna        around 80+
Paul A Molive           Molive Paul         around 80+
Bob Frapples            Frapples Bob        100

注意:上面给出的只是示例数据,我在实际情况中在few records中有table1,在50 millions中有table2

我的尝试

步骤1 :根据Shnugo的建议,具有规范化的数据并存储在同一表中。

对于表1:

ALTER TABLE table1 ADD Name_Normal VARCHAR(1000);
GO

--00:00:00 (5 row(s) affected)
UPDATE table1 
SET Name_Normal=CAST('<x>' + REPLACE((SELECT LOWER(name) AS [*] FOR XML PATH('')),' ','</x><x>') + '</x>' AS XML)
                .query(N'
                        for $fragment in distinct-values(/x/text())
                        order by $fragment
                        return $fragment
                        ').value('.','nvarchar(1000)');           
GO

对于表2:

ALTER TABLE table2 ADD Name_Normal VARCHAR(1000);
GO

--01:59:03 (50000000 row(s) affected)
UPDATE table2 
SET Name_Normal=CAST('<x>' + REPLACE((SELECT LOWER(name) AS [*] FOR XML PATH('')),' ','</x><x>') + '</x>' AS XML)
                .query(N'
                        for $fragment in distinct-values(/x/text())
                        order by $fragment
                        return $fragment
                        ').value('.','nvarchar(1000)');           
GO  

步骤2 :使用Levenshtein distance in Microsoft Sql Server

创建百分比计算功能

步骤3 :查询以获取匹配百分比。

--00:00:33 (23456 row(s) affected)
SELECT t.name AS [tbl1_Name],t1.name AS [tbl2_Name],
       dbo.ufn_Levenshtein(t.Name_Normal,t1.Name_Normal) percentage 
       into #TempTable
FROM table2 t
INNER JOIN table1 t1 
ON CHARINDEX(SOUNDEX(t.Name_Normal),SOUNDEX(t1.Name_Normal))>0 

--00:00:00 (23456 row(s) affected)
SELECT * 
FROM #TempTable 
WHERE percentage >= 50
order by percentage desc;

结论:正在获得预期的结果,但是如上查询中的注释所述,要归一化2 hours大约需要table2。有没有建议在step 1上为table2进行更好的优化?

1 个答案:

答案 0 :(得分:0)

您是否尝试过研究DQS(数据质量服务)? 取决于您的SQL版本,它随安装文件一起提供。 https://docs.microsoft.com/en-us/sql/data-quality-services/data-matching?view=sql-server-2017