Question

A =["I like apple"]
B =["I like playing basketball"]
C =["how are you doing"]
listt=[A,B,C]

我需要返回列表中单词最多的字符串（在此示例中为B和C）。

首先，我想计算每个字符串中的单词数，但是我的代码不起作用。有谁知道如何返回包含最多单词的字符串？

number = len(re.findall(r'\w+',listt))

Answer 1

使用max：

print(max(A+B+C,key=lambda x: len(x.split())))

如果想同时显示两者：

print([i for i in A+B+C if i == max(A+B+C,key=lambda x: len(x.split()))])

Answer 2

尝试一下：

[len(i[0].split(' ')) for i in listt]

Answer 3

您可以.count个空格（分隔单词）：[s for s in sentences if s.count(' ') == max(s.count(' ') for s in sentences)]（s[0]，如果每个句子都在一个单独的列表中，并且可能先获取max以节省时间）

如果您的单词也可以用任何标点符号分隔，则您可能希望使用re，例如在示例中，findall对每个句子进行修饰，例如这个：

import re
pattern = re.compile(r'\w+')
# note I changed some stuff to have words only separated by punctuation
sentences = [["I like:apple"], ["I (really)like playing basketball"], ["how are you doing"]]
current_s = []
current_len = 0
for s in sentences:
    no = len(pattern.findall(s[0]))  # [0] because you have each sentence in a separate list
    if no == current_len:
        current_s.append(s)
    elif no > current_len:
        current_s = [s]
        current_len = no
print('the most number of words is', current_len)
print('\n'.join(current_s))

Answer 4

研究后，我发现使用max函数。使用max函数计算最大单词数，然后打印带有最大单词数的单词。

A ="I like apple"
B ="I like playing basketball" 
C ="how are you doing"
sentences=[A,B,C]

max_words=max(len(x.split(' ')) for x in sentences)

print([i for i in sentences if len(i.split(' '))==max_words])

python的基本逻辑，没有任何特殊功能：

A ="I like apple"
B ="I like playing basketball" 
C ="how are you doing"
sentences=[A,B,C]
max_words=0

for sentence in sentences:
    if len(sentence.split(' '))>max_words:
        max_words=len(sentence.split(' '))

for sentence in sentences:
    if len(sentence.split(' '))==max_words:
        print (sentence)

print(max_sentences)

Answer 5

按单词数划分句子和顺序：

A = ["I like apple"]
B = ["I like playing basketball"]
C = ["how are you doing today?"]

sorted_sentences = sorted([(sentence, len(sentence[0].split(' '))) for sentence in [A, B, C]], key=lambda x: x[1],
                      reverse=True)
print('The sentence: "{}" has the maximum number of words: {}'.format(sorted_sentences[0][0],sorted_sentences[0][1]))

输出

The sentence: "['how are you doing today?']" has the maximum number of words: 5

Answer 6

A = ["I like apple"]
B = ["I like playing basketball"]
C = ["how are you doing"]

items = A + B + C

longest_length = len(max(items, key=lambda k: len(k.split())).split())
result = [i for i in items if len(i.split()) == longest_length]

print(result)

输出：

['I like playing basketball', 'how are you doing']

请注意，max是函数，而不是字符串的长度：

max（）方法返回字符串str中的最大字母字符。

这就是为什么我使用键lambda函数将默认比较更改为字符串key=lambda k: len(k.split())中的单词数的原因

如何在python列表中找到单词最多的句子？

6 个答案: