我是MongoDB的新手,目前正在使用Atlas托管的MongoDB。
我的代码使用PHP MongoDB库。
数据库有一个名为“ transactions”的集合,其结构如下:
[
{
"product":"X",
"customer":"John",
"history":[
{
"payment_date":"2017-07-01",
"status":"paid"
},
{
"payment_date":"2017-08-02",
"status":"paid"
},
{
"payment_date":"2017-09-03",
"status":"paid"
}
]
},
{
"product":"Y",
"customer":"Mary",
"history":[
{
"payment_date":"2017-07-01",
"status":"paid"
},
{
"payment_date":"2017-08-02",
"status":"paid"
},
{
"payment_date":"2017-09-03",
"status":"paid"
}
]
}
]
基于此答案https://stackoverflow.com/a/39549711/1229477,我有以下代码尝试查找付款日期等于2017-08-02的历史记录
$manager = new \MongoDB\Driver\Manager(getenv('MONGODB_DSN'));
$db = new \MongoDB\Database($manager, getenv('MONGODB_DATABASE'));
$cursor = $db->transaction->find(
['history.payment_date' => '2017-08-02'],
['_id' => 0, 'history' => ['$elemMatch' => ['history.payment_date' => '2017-08-02']]]
);
return $cursor->toArray();
但是它不返回任何项目!
我尝试在MongoShell中运行代码!
我还尝试了一些使用聚合的代码:
$manager = new \MongoDB\Driver\Manager(getenv('MONGODB_DSN'));
$db = new \MongoDB\Database($manager, getenv('MONGODB_DATABASE'));
$cursor = $db->transaction->aggregate(
[
[
'$match' => [
'history.payment_date' => "2017-08-02"
]
],
[
'$project' => [
'_id' => 0,
'history' => 1
]
]
]
);
return $cursor->toArray();
我跟踪了很多链接,但其中任何一个都没有成功! 因此,如果您不给我其他链接,我们将不胜感激,因为我已经访问了数百个!
答案 0 :(得分:1)
我会尝试一下:
$cursor = $db->transaction->aggregate(
[
[
'$match' => [
'history.payment_date' => "2017-08-02" // limit returned documents to ones with matches
]
],
[
'$unwind' => "$history" // split each document into multiple documents based on history
],
[
'$match' => [
'history.payment_date' => "2017-08-02" // only return documents that match
]
]
]
);