{
"_id" : NumberLong(107),
"cnic" : NumberLong(098765),
"recordsOFGt" : [
{
"records" : [
{
"_id" : NumberLong(1),
"contactIds" : [
NumberLong(303)
],
},
{
"_id" : NumberLong(2),
"contactIds" : [
NumberLong(303),
NumberLong(304)
],
},
{
"_id" : NumberLong(3),
"contactIds" : [
NumberLong(309),
NumberLong(304)
],
},
{
"_id" : NumberLong(4),
"contactIds" : [
NumberLong(303),
NumberLong(304)
],
},
{
"_id" : NumberLong(5),
"contactIds" : [
NumberLong(303),
NumberLong(304)
],
},
]
},
"records2" : {
...
...
}
]
}
我只想要通过_id
匹配的记录元素我已尝试过这个
db.getCollection('tempCollection').findOne(
{ 'recordsOFGt': {$elemMatch: {'records._id': 1} }},
{'recordsOFGt.$': 1}
)
这将返回记录数组的所有元素,只需匹配元素。
这就是我想要的输出:
{
"records" :
{
"_id" : NumberLong(1),
"contactIds" : [
NumberLong(303)
],
}
}