从二进制搜索功能返回值

时间:2019-02-13 10:23:54

标签: javascript arrays functional-programming binary-search

以下代码对数组进行二进制搜索。我做了艰苦的工作,并获得了理论上可以运行的代码;不幸的是,我无法从函数中返回值;

简而言之,我希望返回“ len”;如果在该行中设置断点,您将看到“ len”包含正确的答案。但是我错过了一些非常愚蠢的东西。请帮助我识别。

var states = ['Alabama','Alaska','American Samoa','Arizona','Arkansas','California','Colorado','Connecticut','Delaware','District of Columbia','Federated States of Micronesia','Florida','Georgia','Guam','Hawaii','Idaho','Illinois','Indiana','Iowa','Kansas','Kentucky','Louisiana','Maine','Marshall Islands','Maryland','Massachusetts','Michigan','Minnesota','Mississippi','Missouri','Montana','Nebraska','Nevada','New Hampshire','New Jersey','New Mexico','New York','North Carolina','North Dakota','Northern Mariana Islands','Ohio','Oklahoma','Oregon','Palau','Pennsylvania','Puerto Rico','Rhode Island','South Carolina','South Dakota','Tennessee','Texas','Utah','Vermont','Virgin Island','Virginia','Washington','West Virginia','Wisconsin','Wyoming'];
function binarySearch(arr1,term){
  var arr = [...arr1],
    len = 0;
  function helper(arr,term) {
    if(arr.length > 1) {
      if(arr[Math.floor(arr.length/2)] === term) {
          len += Math.floor(arr.length/2);
          return len;
      }
      if(arr[Math.floor(arr.length/2)] < term) {
          len += Math.floor(arr.length/2);
          arr.splice(0,Math.floor(arr.length/2));
          helper(arr,term)
      }
      else if (arr[Math.floor(arr.length/2)] > term) {
          arr.splice(Math.floor(arr.length/2),arr.length-1);
          helper(arr,term)
      }
    } else {
        return 'Element not found';
    }
  }
  return helper(arr,term);
}
console.log(binarySearch(states,"Arizona"));

1 个答案:

答案 0 :(得分:1)

您的递归调用也应返回给调用者:

替换:

helper(arr,term)

具有:

return helper(arr,term)

在两个实例上。