尝试输入的代码之一

Question

我必须将xml文件转换为数据框熊猫。我已经在多种模式下尝试过，但结果是相同的：无，无...我错了吗？另一个图书馆更好吗？是否可能是因为我的XML格式？ xml文件的类型为：

<Document xmlns="xxx/zzz/yyy">  
 <Header>    
  <DocumentName>GXXXXXXXXXX</DocumentName>    
  <DocumentType>G10</DocumentType>    
  <Version>2.0.0.0</Version>    
  <Created>2018-12-11T09:00:02.987777+00:00</Created>    
  <TargetProcessingDate>2019-02-11</TargetProcessingDate>    
  <Part>      
  <CurrentPage>1</CurrentPage>      
  <TotalPages>1</TotalPages>    
  </Part>  
 </Header> 
 <Body>    
  <Accounts>      
    <Account>        
     <Type>20WE</Type>        
     <OldType>19WE</OldType>        
     <Kids>          
      <Kid>            
       <Name>marc</Name>            
       <BirthDate>2000-02-06</BirthDate>                       
       <Year>19</Year>            
       <Email>marc@xxx.com</Email>                         
      </Kid>           
     </Kids>      
    </Account>
   </Accounts> 
  </Body>  
</Document>

尝试输入的代码之一

import xml.etree.ElementTree as ET
import pandas as pd
class XML2DataFrame:

   def __init__(self, xml_data):
        self.root = ET.XML(xml_data)

    def parse_root(self, root):
        """Return a list of dictionaries from the text and attributes of the
        children under this XML root."""
        return [parse_element(child) for child in root.getchildren()]

    def parse_element(self, element, parsed=None):
    """ Collect {key:attribute} and {tag:text} from thie XML
     element and all its children into a single dictionary of strings."""
        if parsed is None:
            parsed = dict()

        for key in element.keys():
            if key not in parsed:
                parsed[key] = element.attrib.get(key)
            if element.text:
                parsed[element.tag] = element.text                
            else:
                raise ValueError('duplicate attribute {0} at element {1}'.format(key, element.getroottree().getpath  (element)))           

    """ Apply recursion"""
        for child in list(element):
            self.parse_element(child, parsed)
        return parsed

    def process_data(self):
    """ Initiate the root XML, parse it, and return a dataframe"""
        structure_data = self.parse_root(self.root)
        return pd.DataFrame(structure_data)

xml2df = XML2DataFrame(xml_data)
xml_dataframe = xml2df.process_data()

预期产量

Type  OldType  Name  BirthDate  Year  Email
20WE  19WE     marc  2000-02-06 19    marc@xxx.com

Answer 1

您可以使用xmltodict将其转换为json，然后进行解析：

import xmltodict
import pandas as pd

with open('file.xml', 'r') as f:
    data = xmltodict.parse(f.read())['Document']['Body']['Accounts']['Account']

data_pd = {'Type': [data['Type']],
           'OldType': [data['OldType']],
           'Name': [data['Kids']['Kid']['Name']],
           'BirthDate': [data['Kids']['Kid']['BirthDate']],
           'Year': [data['Kids']['Kid']['Year']],
           'Email': [data['Kids']['Kid']['Email']]}

df = pd.DataFrame(data_pd)
print(df)

输出：

   Type OldType  Name   BirthDate Year         Email
0  20WE    19WE  marc  2000-02-06   19  marc@xxx.com

Answer 2

像genericRetryStrategy = ({ maxRetryAttempts = 3, scalingDuration = 1000, excludedStatusCodes = [], }: { maxRetryAttempts?: number; scalingDuration?: number; excludedStatusCodes?: HttpStatusCode[]; } = {}) => (attempts: Observable<any>) => { return attempts.pipe( mergeMap((error, i) => { this.notificationService.showNotification('attempting', 'retry', 4000, () => { const retryAttempt = i++; // if maximum number of retries have been met // or response is a status code we don't wish the retry, throw error if (retryAttempt > maxRetryAttempts || excludedStatusCodes.find(e => e === error.status)) { return throwError(error); } console.log(`Attempt ${retryAttempt}: retrying in ${retryAttempt * scalingDuration}ms`); //retry after 1s, 2s, etc... return timer(retryAttempt * scalingDuration); }); return throwError(error); }), finalize(() => console.log('We are done!')), ); };

(throwError(error))

输出

BeautifulSoup

将XML转换为Pandas数据框python

尝试输入的代码之一

预期产量

2 个答案: