Question

我正在为C ++中的double分配一个指针。当我取出指针时，它运行良好，但是当我使用指针运行它时，我收到一条错误消息：“无法在分配中将'double *'转换为'double'”。我不知道为什么这会给我这个错误。任何帮助是极大的赞赏。

#include <iostream>
#include <iomanip>


using namespace std;

int main() {
    double ROP, HW, OT,oSal;
    int choice;
    char choice2= (toupper(choice2));
    double * pbsal[2];
    double bsal[2];




   cout<<setprecision (2)<<fixed;

   cout<<"Welcome to the salary calculator!!!"<< endl;
   cout<<""<<endl;
   cout<<"Please enter your hourly rate: "<<endl;
   cin>>ROP;

   while(choice != 3){
   cout<<"Would you like to:"<<endl;
   cout<<"1. Enter the number of hours you worked?"<<endl;
   cout<<"2. Enter the number of overtime hours you worked?"<<endl;
   cout<<"3. Exit the program"<< endl;
   cin>>choice;

   switch(choice){
   case 1:
       cout<<"Please enter the number of hours you worked(excluding 
overtime):"<<endl;
       cin>>HW;
       cout<<"Would you like to see your salary based on the number of 
hours you worked?"<<endl;
       cin>> choice2;
       break;

    case 2:
        cout<<"Please enter the number of hours of overtime you worked:"<< 
endl;
        cin>>OT;

        oSal = (ROP*1.5)*OT;

        cout<<"Your overtime salary is: $"<<oSal<<endl;
        break;



    }
    switch(choice2){
    case 'Y':

        for(int i =0; i<=2; i++){
            bsal[i]=ROP*HW;
            *pbsal[i]= &bsal[i];
        }
        cout<<"Your salary based on the hours you provided is: $" 
<<bsal<<endl;
        cout<<"test"<<*pbsal[0]<<endl;
        cout<<""<<endl;
        break;

    case 'N':
        cout<<"Thank you!"<<endl;
        cout<<""<<endl;
        break;
    }
}
}

这是我收到的错误：

15:45:42 **** Incremental Build of configuration Debug for project Module4 ****
make all 
Building file: ../src/Module4.cpp
Invoking: Cygwin C++ Compiler
g++ -O0 -g3 -Wall -c -fmessage-length=0 -MMD -MP -MF"src/Module4.d" -MT"src/Module4.o" -o "src/Module4.o" "../src/Module4.cpp"
../src/Module4.cpp: In function 'int main()':
../src/Module4.cpp:64:25: error: cannot convert 'double*' to 'double' in assignment
       *pbsal[i]= &bsal[i];
                         ^
make: *** [src/subdir.mk:20: src/Module4.o] Error 1
"make all" terminated with exit code 2. Build might be incomplete.

我希望能够将指针分配为双精度型。

Answer 1

C ++中的指针与C指针略有不同。应该使用关键字new调用它，以进行有效的内存管理。 double *pbsal = new double[2];

现在pbsal[0]和pbsal[1]只是双精度值。循环应该是i<2而不是i<=2。

bsal[i]   = ROP*HW;
pbsal[i]  = bsal[i];

为什么将指针分配给double变量时出现错误

1 个答案: