Question

我的问题很简单：我想列出“表单”表中的所有内容，如果“杰出”表中没有与此“表单”的任何匹配项，那么该行也应仅在表中用NULL列出。 PAYED_GROSS_AMOUNT列（例如，“未完成”表用于此列）。现在，通过此查询，我得到的只是“表单”匹配项，在“杰出”表中也具有匹配项：

SELECT 
    `f`.`ID`                            AS `ID`,
    `f`.`FORM_NR`                           AS `form_nr`,
    `f`.`DELIVERY_DATE`                         AS `delivery_date`,
    `f`.`FORM_DATE`                         AS `form_date`,
    `f`.`PAYMENT_DATE`                      AS `payment_date`,
    MAX(`os`.`PAYED_DATE`)                      AS `payed_date`,
    `fi`.`GROSS_MONEY`                          AS `gross_money`,
    `fi`.`NET_PRICE`                        AS `net_price`,
    ifnull(SUM(`os`.`PAYED_GROSS_AMOUNT`), 0)                       AS `payed_gross_amount`,
    ifnull((`fi`.`GROSS_MONEY`  
     - SUM(`os`.`PAYED_GROSS_AMOUNT`)),
     `fi`.`GROSS_MONEY`)                        AS `remaining_amount`
    FROM  `form` `f`
    LEFT JOIN `outstanding` `os` ON `f`.`ID` = `os`.`INVOICE_ID`,
    (SELECT form_id          AS `FORM_ID`, 
                  SUM(gross_money) AS `GROSS_MONEY`, 
                  SUM(net_price)   AS `NET_PRICE` 
           FROM   form_item
           GROUP  BY form_id) fi
    WHERE `f`.SUBTYPE <> 3
    AND   `fi`.FORM_ID = `f`.ID
    AND   `f`.STATUS = 2
    AND   `f`.DIRECTION = 1
    AND   `os`.DELETED <> 'deleted' 
    AND   (`f`.PAYMENT_TYPE = 2 OR `f`.PAYMENT_TYPE = 4)
    AND   `f`.FORM_TYPE = 'Invoice'
    AND `f`.deleted <> 'deleted' 
    GROUP BY `f`.`ID`, 
             `fi`.`form_id` 
    ORDER BY `f`.`FORM_DATE` DESC;

我也尝试了LEFT OUTER JOIN，但是没有运气：（

谢谢！

编辑：

查询尽可能简化（最后可以忽略WHERE子句）

预期结果：

表单表：

ID FORM_NR ...
1  2019/1
2  2019/2
3  2019/4
4  2019/7
...

杰出表：

INVOICE_ID  PAYED_DATE  PAYED_GROSS_AMOUNT ...
2           2019-02-05  100
3           2019-02-06  200
...

结果：

FORM_NR  FORM_DATE  ... PAYED_DATE  PAYED_GROSS_AMOUNT
2019/1   2019-02-01     null        0
2019/2   2019-02-02     2019-02-05  100
2019/4   2019-02-03     2019-02-06  200
2019/7   2019-02-04     null        0
...

PAYED_GROSS_AMOUNT是因为IFNULL方法0而不是NULL。

Answer 1

使用NOT EXISTS。像这样：

select . . .
from form f
where <conditions on form> and
      not exists (select 1
                  from outstanding o
                  where o.form_item = f.id and
                        <conditions on outstanding>
                 );

如果另一个表中没有匹配项，则将连接列列为空值

1 个答案: