Question

我有一个（postgres）sql表，其中包含以下内容（主机）：

   ip_address   |  mac_address   | hostname | device | physical_port
----------------+----------------+----------+--------+---------------
111.111.111.111 | aaaa.aaaa.aaaa | hosta    | swh-a  | Gi1/1
111.111.111.112 | bbbb.bbbb.bbbb | hostb    | swh-b  | Gi2/1
111.111.111.113 | cccc.cccc.cccc | hostc    | swh-c  | Gi3/1

我有另一个表（Peers），其中包含功能表中devices之间的点对点链接。

 device | physical_port | peer_device | peer_physical_port 
 -------+---------------+-------------+----------------------+
 swh-a  | Gi1/20        | swh-b       | Gi2/1
 swh-b  | Gi2/1         | swh-a       | Gi1/20
 swh-b  | Gi2/1         | swh-c       | Gi3/1
 swh-c  | Gi3/1         | swh-b       | Gi2/1

基本上，我希望Peers表中包含的Hosts表中的排除条目，这样我才能得到：

   ip_address   |  mac_address   | hostname | device | physical_port
----------------+----------------+----------+--------+---------------
111.111.111.111 | aaaa.aaaa.aaaa | hosta    | swh-a  | Gi1/1

（鉴于Peers表中存在device=swh-b physical_port=Gi2/1和device=swh-c physical_port=Gi3/1）。

Answer 1

您可以使用NOT EXISTS进行自解释查询，该查询几乎就像是英文一样：

SELECT *
FROM Hosts h
WHERE NOT EXISTS (
    SELECT * FROM Peers p
    WHERE p.peer_device = h.device AND p.peer_physical_port = h.physical_port
)

Answer 2

这对你有用吗？

SELECT * FROM Hosts
WHERE NOT peer_physical_port IN (
    SELECT DISTINCT peer_physical_port FROM Peers
)

您只选择未出现在第二个表格中的条目。

Answer 3

你需要这样的东西：

SELECT *
FROM Host h
LEFT JOIN Peers p ON p.device= h.device and p.physical_port = h.physical_port
WHERE p.ID IS NULL

Answer 4

试试这个..

SELECT  * 
FROM    Host
WHERE   device NOT IN (SELECT device FROM Peers )
AND     physical_port NOT IN (SELECT physical_port FROM Peers)

仅当没有匹配时才进行SQL连接

4 个答案: