我想将输入追加到2D数组中的特定位置。该任务是输入我自己的数据来替换数组中的位置。
#Array
Days = ["Mon 1","Tue 1","Wed 1","Thu 1","Fri 1",
"Mon 2","Tue 2","Wed 2","Thu 2","Fri 2",
"Mon 3","Tue 3","Wed 3" ,"Thu 3","Fri 3",
"Mon 4","Tue 4","Wed 4","Thu 4","Fri 4"]
Route = ["Bus A","Bus B","Bus C","Bus D","Bus E","Bus F"]
#The array in each bus is (Mon 1 - Fri 4 in each bus)
BusData = [[0,0,0,2,2,4,0,3,4,-2,-5,0,0,3,4,-1,8,1,1,-2], #Bus A
[0,1,0,0,1,2,0,0,0,0,1,0,0,0,2,0,0,1,0,0], #Bus B
[2,0,-1,-1,-2,-2,-3,-1,0,0,-2,0,1,1,1,1,-1,-1,2,-1], #Bus C
[1,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0], #Bus D
[-1,-1,-1,-2,-4,-10,-2,0,0,0,0,1,2,-3,1,1,3,-1,0,0], #Bus E
[0,-5,-5,-5,-4,-3,-5,0,0,0,0,-2,-3,1,1,1,0,0,-2,-5]] #Bus F
例如，我输入了日期和路线，并尝试使用索引位置将其放置在数组中。
我试图做这样的解决方案：
#Input values in array
for i in Route: #Finding index of input in array
if Bus == i:
RoutePos = Route.index(i)
for i in Days: #Finding index of input in array
if Day == i:
DayPos = Days.index(i)
DataPos = BusData[RoutePos][DayPos]
BusData.append(DataPos)
print(BusData)
如果有人要我详细说明这个问题，请告诉我
答案 0 :(得分：1)
您已经结合了几种解决方案；这不是必需的。您只需查找路线和日期索引：
route_pos = Route.index(Bus)
day_pos = Days.index(Day)
BusData.append(BusData[route_pos][day_pos]
但是，我根本不确定这就是您想要的。这样会将一个整数附加到2D列表中，例如：
[[0,0,0,2,2,4,0,3,4,-2,-5,0,0,3,4,-1,8,1,1,-2], #Bus A
[0,1,0,0,1,2,0,0,0,0,1,0,0,0,2,0,0,1,0,0], #Bus B
[2,0,-1,-1,-2,-2,-3,-1,0,0,-2,0,1,1,1,1,-1,-1,2,-1], #Bus C
[1,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0], #Bus D
[-1,-1,-1,-2,-4,-10,-2,0,0,0,0,1,2,-3,1,1,3,-1,0,0], #Bus E
[0,-5,-5,-5,-4,-3,-5,0,0,0,0,-2,-3,1,1,1,0,0,-2,-5], #Bus F
2 # New element
]
答案 1 :(得分：0)
首先，python使用列表而不是数组。 要附加到列表，请使用.append函数 例如：
List_name.append(Insert_data_to_append_here)
在您的情况下：
BusData.append(BusData[route_pos][day_pos])
代替：
DataPos = BusData[RoutePos][DayPos]
BusData.append(DataPos)
因此它可以合并为一行，因为它使它更整洁。
答案 2 :(得分：0)
我不确定这是否合适，因为您可能需要列表形式的数据。但是如果没有的话，熊猫将变得无关紧要。
import pandas as pd
# the fourth row had an extra digit, I deleted a zero
df = pd.DataFrame(data=BusData, index=Route, columns=Days)
df=df.T
df.loc['Mon 1', 'Bus B'] = 25
df.loc['Wed 1'] = 100
df.loc[:,'Bus F'] = 999
df
Bus A Bus B Bus C Bus D Bus E Bus F
Mon 1 0 25 2 1 -1 999
Tue 1 0 1 0 0 -1 999
Wed 1 100 100 100 100 100 999
Thu 1 2 0 -1 0 -2 999
Fri 1 2 1 -2 0 -4 999
Mon 2 4 2 -2 0 -10 999
Tue 2 0 0 -3 0 -2 999
Wed 2 3 0 -1 0 0 999
Thu 2 4 0 0 0 0 999
Fri 2 -2 0 0 0 0 999
Mon 3 -5 1 -2 2 0 999
Tue 3 0 0 0 0 1 999
Wed 3 0 0 1 0 2 999
Thu 3 3 0 1 0 -3 999
Fri 3 4 2 1 0 1 999
Mon 4 -1 0 1 0 1 999
Tue 4 8 0 -1 0 3 999
Wed 4 1 1 -1 0 -1 999
Thu 4 1 0 2 0 0 999
Fri 4 -2 0 -1 0 0 999
答案 3 :(得分：0)
由于尚不清楚您要寻找的是什么，因此，根据您的澄清，此答案假设以下三个条件：
Bus是Route Day是Days BusData按照Route和Days的相同顺序排序。然后就这么简单：
route_pos = Route.index(Bus)
day_pos = Days.index(Day)
BusData[route_pos][day_pos] == some_data_to_replace
some_data_to_replace是您要替换的特定Bus和Day的路线信息。
例如：
Bus = input("Enter the exact bus info: ") # e.g. "Bus C"
Day = input("Enter the exact day info: ") # e.g. "Mon 2"
Data = int(input("Enter the route info to replace: ")) # e.g. 99
route_pos = Route.index(Bus) # position 2
day_pos = Days.index(Day) # position 5
BusData[route_pos][day_pos] == some_data_to_replace # "row" 2, "col" 5 is replaced
BusData
# [[0,0,0,2,2,4,0,3,4,-2,-5,0,0,3,4,-1,8,1,1,-2], # Bus A
# [0,1,0,0,1,2,0,0,0,0,1,0,0,0,2,0,0,1,0,0], # Bus B
# [2,0,-1,-1,-2,99,-3,-1,0,0,-2,0,1,1,1,1,-1,-1,2,-1], # Bus C (pos 2) Mon 1 (pos 5) is replaced
# [1,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0], # Bus D
# [-1,-1,-1,-2,-4,-10,-2,0,0,0,0,1,2,-3,1,1,3,-1,0,0], # Bus E
# [0,-5,-5,-5,-4,-3,-5,0,0,0,0,-2,-3,1,1,1,0,0,-2,-5]] # Bus F