我正在尝试将一个整数数组（最终被转换为它们的ASCII字符）放入一个数组中，由星星构成，但它不起作用，我不知道为什么。
我的代码如下，数据是一个包含40列和22行的数组。
image = Array.new(24) { Array.new(42, ' ')}
(0..23).each do |r|
if r == 0 || r == 23 then
(0..41).each do |c|
image[r][c] = '*'
end
else
(0..41).each do |c|
if c == 0 || c == 41 then
image[r][c] = '*'
else
image[r][c] = data[r][c]
end
end
end
end
print image
答案 0 :(得分：0)
你这样做太复杂了。把它分解成几步。删除嵌套循环和条件。
1）抓取图像中的第0行和第23行，并将所有内容设置为“*”。
2）遍历每一行（即image.each do |row| ...）并将第0列和第41列设置为“*”。
3）再次遍历每一行，并设置其他列以匹配数据中的内容（这里可能需要嵌套循环，但没有条件）。
编辑：完整代码看起来像这样：
#step0 -- create nested array with first and last rows missing. Doesn't need useless spaces. Nil instead.
image = Array.new(22) { Array.new(42) }
#step1 --- iterate through the rows and set first and last columns to "*"
image.each do |row|
row[0] = "*"
row[41] = "*"
end
#step2 -- add first and last rows, which are all "*"
image.shift(Array.new(42, "*"))
image.push(Array.new(42, "*"))
#step3 -- nested loop that matches image to data only if not already set.
image.each_with_index do |row, ridx|
row.each_with_index do |col, cidx|
image[row][col] = data[row][col] unless image[row][col]
end
end
实际上，克隆数据然后向其添加边框可能更容易。毕竟，你在这里所做的一切，都可能是你所遇到的问题的根源。
答案 1 :(得分：0)
如果我理解你的情况并且你有下一个值：
image = Array.new(5) { Array.new(10, ' ')}
data = [[0, 1, 2, 3, 4, 5, 6, 7], [8, 9, 10, 11, 12, 13, 14, 15], [16, 17, 18, 19, 20, 21, 22, 23]]
然后，代码的最小编辑应如下所示：
(0..4).each do |r|
(0..9).each do |c|
if r == 0 || r == 4 || c == 0 || c == 9
image[r][c] = '*'
else
image[r][c] = data[r.pred][c.pred]
end
end
end
然后结果如下：
> image
#=> [["*", "*", "*", "*", "*", "*", "*", "*", "*", "*"], ["*", 0, 1, 2, 3, 4, 5, 6, 7, "*"], ["*", 8, 9, 10, 11, 12, 13, 14, 15, "*"], ["*", 16, 17, 18, 19, 20, 21, 22, 23, "*"], ["*", "*", "*", "*", "*", "*", "*", "*", "*", "*"]]
答案 2 :(得分：0)
让我们先构建data。为简单起见，我假设data有6个元素（＆＃34;行＆＃34;），每个元素都是4个元素的数组（形成＆＃34;列＆＃34;，虽然Ruby实际上没有具有行和列的数组的概念）。
ROWS = 6
COLS = 4
data = (ROWS*COLS).times.to_a.each_slice(4).to_a
#=> [[0, 1, 2, 3], [4, 5, 6, 7], [8, 9, 10, 11], [12, 13, 14, 15],
# [16, 17, 18, 19], [20, 21, 22, 23]]
现在我们只需稍微修改您的代码即可产生所需的结果。
rows = data.size+2
#=> 8
cols = data.first+2
#=> 6
image = Array.new(rows) { Array.new(cols, ' ')}
(0...rows).each do |r| # note 3 dots here and below
if r == 0 || r == rows-1
(0...cols).each do |c|
image[r][c] = '*'
end
else
(0...cols).each do |c|
if c == 0 || c == cols-1
image[r][c] = '*'
else
image[r][c] = data[r-1][c-1]
end
end
end
end
image.each { |row| p row }
打印
["*", "*", "*", "*", "*", "*"]
["*", 0, 1, 2, 3, "*"]
["*", 4, 5, 6, 7, "*"]
["*", 8, 9, 10, 11, "*"]
["*", 12, 13, 14, 15, "*"]
["*", 16, 17, 18, 19, "*"]
["*", 20, 21, 22, 23, "*"]
["*", "*", "*", "*", "*", "*"]
更像Ruby的方法如下：
image = [['*']*(data.first.size+1)]
ROWS.times { |i| image << ['*', *data[i], '*'] }
image << image.first
image.each { |row| p row }
如果您想要生成格式良好的表格，则可以执行以下操作。
def fmt(data, col_space, boundary_char='*')
col_width = data.flatten.map { |n| n.to_s.size }.max + col_space
nrows, ncols = data.size, data.first.size
header = boundary_char * (col_width * ncols + 2 + col_space)
right_border = " "*col_space << boundary_char
image = [header]
data.each { |row|
image << "%s%s%s" %
[boundary_char, row.map { |n| n.to_s.rjust(col_width) }.join, right_border] }
image << header
image
end
puts fmt(data, 2)
打印
********************
* 0 1 2 3 *
* 4 5 6 7 *
* 8 9 10 11 *
* 12 13 14 15 *
* 16 17 18 19 *
* 20 21 22 23 *
********************
步骤如下（data，如上所述）。
col_space = 2
boundary_char='*'
a = data.flatten
#=> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,
# 15, 16, 17, 18, 19, 20, 21, 22, 23]
b = a.map { |n| n.to_s.size }
#=> [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2]
col_width = b.max + col_space
#=> 2 + 2 => 4
nrows, ncols = data.size, data.first.size
#=> [6, 4]
header = boundary_char * (col_width * ncols + 2 + col_space)
#=> * * (4*4 + 2 + 2)
#=> "********************"
right_border = " "*col_space << boundary_char
#=> " "*2 << "*" =< " " << "*" => " *"
image = [header]
#=> ["********************"]
data.each { |row|
puts "row=#{row}"
puts " image row=#{"%s%s%s" % [boundary_char,
row.map { |n| n.to_s.rjust(col_width) }.join, right_border]}"
image << "%s%s%s" % [boundary_char,
row.map { |n| n.to_s.rjust(col_width) }.join, right_border] }
row=[0, 1, 2, 3]
image row=* 0 1 2 3 *
row=[4, 5, 6, 7]
image row=* 4 5 6 7 *
row=[8, 9, 10, 11]
image row=* 8 9 10 11 *
row=[12, 13, 14, 15]
image row=* 12 13 14 15 *
row=[16, 17, 18, 19]
image row=* 16 17 18 19 *
row=[20, 21, 22, 23]
image row=* 20 21 22 23 *
然后
image << header
image
返回上面的结果。