从图像中提取特定的文本关联值

时间:2019-02-06 18:03:17

标签: python opencv ocr

我有一张图片,我想从图片中提取键和值对的详细信息。

例如,我要提取“ MASTER-AIRWAYBILL NO:”的值

Image

我已经写过使用python opencv和OCR从图像中提取整个文本的方法,但是我不知道如何从图像的整个结果文本中提取“ MASTER-AIRWAYBILL NO:”的值

请找到代码:

import cv2
import numpy as np
import pytesseract
from PIL import Image
print ("Hello")
src_path = "C:\\Users\Venkatraman.R\Desktop\\alpha_bill.jpg"
pytesseract.pytesseract.tesseract_cmd = r"C:\Program Files (x86)\Tesseract-OCR\tesseract.exe"


print (src_path)


# Read image with opencv
img = cv2.imread(src_path)

# Convert to gray
img = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)

# Apply dilation and erosion to remove some noise
kernel = np.ones((1, 1), np.uint8)
img = cv2.dilate(img, kernel, iterations=1)
img = cv2.erode(img, kernel, iterations=1)

# Write image after removed noise
cv2.imwrite(src_path + "removed_noise.png", img)

#  Apply threshold to get image with only black and white
#img = cv2.adaptiveThreshold(img, 255, cv2.ADAPTIVE_THRESH_GAUSSIAN_C, cv2.THRESH_BINARY, 31, 2)

# Write the image after apply opencv to do some ...
cv2.imwrite(src_path + "thres.png", img)

# Recognize text with tesseract for python
result = pytesseract.image_to_string(Image.open(src_path + "thres.png"))


# Remove template file
#os.remove(temp)


print ('--- Start recognize text from image ---')
print (result)

所以输出应该像这样:

  

航空总运单号:157-46637194

3 个答案:

答案 0 :(得分:0)

您可以使用pytesseract image_to_string()regex提取所需的文本,即:

from PIL import Image
import pytesseract, re
f = "ocr.jpg"
t = pytesseract.image_to_string(Image.open(f))
m = re.findall(r"MASTER-AIRWAYBILL NO: [\d—-]+", t)
if m:
    print(m[0])

输出:

MASTER-AIRWAYBILL NO: 157—46637194

答案 1 :(得分:0)

我正在使用python 2.7,我也想从图像中找到供应商名称 我应该怎么找到?

m = re.findall(r“ MASTER-AIRWAYBILL NO:[\ d ---] +”,t) 对于上面的行,其显示错误

如果我使用m = re.findall(r'Vendor Name:[\ d-] +',t),那么它也显示错误

答案 2 :(得分:0)

您可以在安装tesseract之后尝试一下。

from PIL import Image
import pytesseract, re
pytesseract.pytesseract.tesseract_cmd = r"C:\Program Files\Tesseract-OCR\tesseract.exe"
t = pytesseract.image_to_string(Image.open("path"))
m = re.findall(r"Invoice No. [\d—-]+", t)
if m:
    print(m[0])