我有一个剧本互动类,可以从postgres DB中进行选择。我想知道如何使用返回这个剧本模式的结果集。
我现在尝试的是将方法“ public void performAs(T actor)”的返回类型更改为“ public ResultSet performAs(T actor)”
但是,我具有以下问题:
Error:(12, 8) java: jarv.serenity.carnival.interactions.dbRelated.SelectDataBase is not abstract and does not override abstract method <T>performAs(T) in net.serenitybdd.screenplay.Performable
Error:(23, 40) java: <T>performAs(T) in jarv.serenity.carnival.interactions.dbRelated.SelectDataBase cannot implement <T>performAs(T) in net.serenitybdd.screenplay.Performable
return type java.sql.ResultSet is not compatible with void
Error:(21, 5) java: method does not override or implement a method from a supertype
这是课程文件
package jarv.serenity.carnival.interactions.dbRelated;
import jarv.serenity.carnival.dataBaseConection.DataBaseDriver;
import jarv.serenity.carnival.model.Users;
import net.serenitybdd.screenplay.Actor;
import net.serenitybdd.screenplay.Interaction;
import net.thucydides.core.annotations.Step;
import java.sql.ResultSet;
import java.sql.Statement;
import static net.serenitybdd.screenplay.Tasks.instrumented;
public class SelectDataBase implements Interaction {
private final DataBaseDriver dbDriver;
private ResultSet rs=null;
public SelectDataBase(DataBaseDriver dbDriver) {
this.dbDriver = dbDriver;
}
@Override
@Step("Selecting from DB")
public <T extends Actor> void performAs(T actor) {
try
{
Statement st = dbDriver.getConn().createStatement();
rs = st.executeQuery("SELECT * From users");
dbDriver.disconect();
}
catch(Exception e)
{
dbDriver.disconect();
System.out.println(e);
}
}
public ResultSet getResults(){
return rs;
}
public static Interaction select(DataBaseDriver dbDriver) {
return instrumented(SelectDataBase.class, dbDriver);
}
@Override
public String toString() {
return rs.toString();
}
}
现在,我能够进行选择操作,但没有检索结果集。
我想能够检索它还是有它返回的任何任务或使用该互动问题
答案 0 :(得分:0)
在Screenplay模式中,交互并不意味着返回值,而只是为了在被测系统上执行某些操作。您可以使用Questions查询系统状态。如果您共享要解决的总体问题会更容易,但是由于您的示例是关于查询用户的,因此您可以进行一项测试,以检查是否可以通过UI管理员页面将用户添加到系统中。
@Test
public void add_a_user_to_the_system() {
Actor ada = Actor.named("Ada").describedAs("an admin");
when(ada).attemptsTo(
AddANewUser.called("Jack")
);
then(ada).should(
seeThat(KnownUsers.inTheSystem(),
contains(hasProperty("name", equalTo(("Jack"))))
)
);
}
(在这种情况下,按名称搜索用户可能会更有效,但我想使其与您的示例保持一致)。
为此,您可能有一个AddANewUser
类,该类使用管理屏幕来添加新用户:
class AddANewUser implements Performable {
public static Performable called(String userName) {
return instrumented(AddANewUser.class, userName);
}
private final String userName;
AddANewUser(String userName) {
this.userName = userName;
}
@Override
public <T extends Actor> void performAs(T actor) {
// Add a new user called userName via the UI
}
}
然后,您将使用以下问题检查该用户的存在:
@Subject("known users")
static class KnownUsers implements Question<List<ApplicationUser>> {
public static KnownUsers inTheSystem() { return new KnownUsers(); }
@Override
public List<ApplicationUser> answeredBy(Actor actor) {
// Query the database and convert the result set to ApplicationUsers
return ...;
}
}
您还可以创建一个Ability类来集中化JDBC查询,凭据等。