我正在与Cypress FX3 kit设备通信。
我使用以下方式发送信息:
unsigned int file_size;
unsigned short wLength = 16;
unsigned int timeout = 1000;
unsigned short wValue = 0, wIndex = 1;
/* Here I get my file_size value */
file_size = 4000; // For the sake of the example.
rStatus = libusb_control_transfer(
device_handle, /* a handle for the device to communicate with */
WRITE_REQUEST_TYPE, /* bmRequestType: the request type field for the setup packet */
VND_CMD_SLAVESER_CFGLOAD, /* bRequest: the request field for the setup packet */
wValue, /* wValue: the value field for the setup packet */
wIndex, /* wIndex: the index field for the setup packet */
(unsigned char *) &file_size, /* *data: a suitably-sized data buffer */
wLength, /* wLength: the length field for the setup packet. The data buffer should be at least this size. */
timeout); /* timeout (in millseconds) that this function should wait before giving up due to no response being received. For an unlimited timeout, use value 0. */
现在我的计划是获得正确的信息。我向我的计算机发送UART消息,实际上FX3固件正在获取所需的内容,并随其所需的内容进行处理,但是cpp程序从不退出 libusb_control_transfer
函数。>
至少不应该暂停以防止该函数永不返回吗?还是因为它能够发送数据而不能阻止它……是否在等待FX3固件不发送的ACK?我不知道该如何调试。
在某些情况下,我还会在Process finished with exit code 139 (interrupted by signal 11: SIGSEGV).
里面找到libusb_control_transfer
(我打印了一下,发现它确实在里面)。
答案 0 :(得分:0)
我解决了这个问题。我给它的device_handle并不总是相同的。取决于它的值,它会出现细分错误,或者永远不会从函数返回。
我给了它正确的手柄,现在可以正常工作了。