Question

我有一个数组作为源。我想通过使用Groovy将源转换为结果。我没有看到任何类似的问题。这就是为什么我在这里发布。

我试图获得该家族中的第一个成员，并使用此代码将所有其他成员放入一个subList中，但失败了

source.each{ family -> family.each{ 
        member -> member.get(0).collate(1,family.size()-1)
    }
}

来源：

[
  [{
        "id": "0001",
        "role": "parent",
        "age": 30
    },
    {
        "id": "0002",
        "role": "child",
        "age": 1
    },
    {
        "id": "0003",
        "role": "child",
        "age": 3
    }
],
[{
        "id": "0004",
        "role": "parent",
        "age": 31
    },
    {
        "id": "0005",
        "role": "child",
        "age": 5
    }
  ]
]

结果：

[{
    "id": "0001",
    "role": "parent",
    "age": 30,
    "children": [{
            "id": "0002",
            "role": "child",
            "age": 1
        },
        {
            "id": "0003",
            "role": "child",
            "age": 3
        }
    ]
},
{
    "id": "0004",
    "role": "parent",
    "age": 31,
    "children": [{
        "id": "0005",
        "role": "child",
        "age": 5
    }]
}]

Answer 1

您可以通过在“父”地图上添加仅包含子地图的新地图来成形数据（groovy中的+会合并）。例如：

def data = new groovy.json.JsonSlurper().parseText('[[{ "id": "0001", "role": "parent", "age": 30 }, { "id": "0002", "role": "child", "age": 1 }, { "id": "0003", "role": "child", "age": 3 } ], [{ "id": "0004", "role": "parent", "age": 31 }, { "id": "0005", "role": "child", "age": 5 }]]')

println(data.collect{ groups ->
    // XXX
    groups.find{ it.role=="parent" } + [children: groups.findAll{it.role=="child"}] 
})
// => [[id:0001, role:parent, age:30, children:[[id:0002, role:child, age:1], [id:0003, role:child, age:3]]], [id:0004, role:parent, age:31, children:[[id:0005, role:child, age:5]]]]

GROOVY将单个数组转换为深层嵌套数组

1 个答案: