Question

我有一个任务对象数组，我想将它们转换为按ownerID分组的多维对象

var tasks = [   
{taskID: "1", title: "task1", ownerID: "100", ownerName: "John", allocation: 80},       
{taskID: "2", title: "task2", ownerID: "110", ownerName: "Sarah", allocation: 50}, 
{taskID: "3", title: "task3", ownerID: "110", ownerName: "Sarah", allocation: 50}, 
{taskID: "4", title: "task4", ownerID: "120", ownerName: "Mike", allocation: 25},
{taskID: "5", title: "task5", ownerID: "120", ownerName: "Mike", allocation: 45}];

这是我的预期输出：

var people = {

    100:    {   ownerName: "John", 
                tasks:  {       
                            {taskID: "1", title: "task1", allocation: 80}
                        }       
            },

    110:    {   ownerName: "Sarah", 
                tasks:  {       
                            {taskID: "2", title: "task2", allocation: 50}
                            {taskID: "3", title: "task3", allocation: 50}
                        }       
            },

    120:    {   ownerName: "Mike", 
                tasks:  {       
                            {taskID: "4", title: "task4", allocation: 25}
                            {taskID: "5", title: "task5", allocation: 45}
                        }       
            },


    };

我循环遍历原始数据并分配每一行

people[ownerID] = {};
person = people[ownerID];
person['ownerName'] = ownerName;
person['tasks'] = {};
person[taskID] = {};
task = person[taskId];
task['taskID'] = taskID;

这似乎按ownerID分组并创建了一个嵌套的任务对象，但它只会为每个人添加一个任务。

哎呀。任何帮助真的很感激。

Answer 1

这是一种功能性的方法（假设 ownerName 功能依赖于 ownerID ）：

const tasks = [   
  {taskID: "1", title: "task1", ownerID: "100", ownerName: "John", allocation: 80},       
  {taskID: "2", title: "task2", ownerID: "110", ownerName: "Sarah", allocation: 50}, 
  {taskID: "3", title: "task3", ownerID: "110", ownerName: "Sarah", allocation: 50}, 
  {taskID: "4", title: "task4", ownerID: "120", ownerName: "Mike", allocation: 25},
  {taskID: "5", title: "task5", ownerID: "120", ownerName: "Mike", allocation: 45}];

const result = tasks.reduce( (acc, {taskID, title, ownerID, ownerName, allocation }) => {
    (acc[ownerID] = acc[ownerID] || { ownerName, tasks: [] })
        .tasks.push( { taskID, title, allocation } );
    return acc;
}, {});

console.log(result);

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Answer 2

people[ownerID] = {};

person['tasks'] = {};

这些行不会检查之前是否存在具有相同键的对象，并且每次都会创建一个新对象。

尝试将其更改为

people[ownerID] = people[ownerID] || {};

person['tasks'] = person['tasks'] || {};

Answer 3

只有一件事，任务应该是一个数组，因为对象无法在没有密钥的情况下持有另一个对象。

var tasks = [   
{taskID: "1", title: "task1", ownerID: "100", ownerName: "John", allocation: 80},       
{taskID: "2", title: "task2", ownerID: "110", ownerName: "Sarah", allocation: 50}, 
{taskID: "3", title: "task3", ownerID: "110", ownerName: "Sarah", allocation: 50}, 
{taskID: "4", title: "task4", ownerID: "120", ownerName: "Mike", allocation: 25},
{taskID: "5", title: "task5", ownerID: "120", ownerName: "Mike", allocation: 45}];

var transformed = tasks.reduce((obj, item)=> {
    if(!obj[item.ownerID]) {
        obj[item.ownerID] = {};
    }
    obj[item.ownerID].ownerName = item.ownerName;
    if(!obj[item.ownerID].tasks) {
        obj[item.ownerID].tasks = [];
    }
    obj[item.ownerID].tasks.push({taskID: item.taskID, title: item.title, allocation: item.allocation})
    return obj;
}, {})
console.log(transformed);

Answer 4

如果peroperty不存在，您可以使用逻辑OR作为默认运算符并分配新对象。

＆＃13;

var tasks = [{ taskID: "1", title: "task1", ownerID: "100", ownerName: "John", allocation: 80 }, { taskID: "2", title: "task2", ownerID: "110", ownerName: "Sarah", allocation: 50 }, { taskID: "3", title: "task3", ownerID: "110", ownerName: "Sarah", allocation: 50 }, { taskID: "4", title: "task4", ownerID: "120", ownerName: "Mike", allocation: 25 }, { taskID: "5", title: "task5", ownerID: "120", ownerName: "Mike", allocation: 45 }],
    people = {};

tasks.forEach(({ taskID, title, ownerID, ownerName, allocation }) => {
    people[ownerID] = people[ownerID] || { ownerName, tasks: {} };
    people[ownerID].tasks[taskID] = people[ownerID].tasks[taskID] || { taskID, title, allocation };
});

console.log(people);

＆＃13;

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＆＃13;

将平面对象数组转换为嵌套对象

4 个答案: