Question

我有一个具有以下结构的文件：

import xlsxwriter

table = [[a, b], [c, d], [e, f, g]] #table must be your matrix 

workbook = xlsxwriter.Workbook('excelFile.xlsx')
worksheet = workbook.add_worksheet()
col = 0

for row, data in enumerate(table):
    worksheet.write_row(row, col, data)

workbook.close()

我想按第4个字段（基本上是按最后一个数字排序）将其按两行乘两行的顺序进行排序，以输出以下结果：

A   35  74  dsadasd/1   0   +
A   95  74  dsadasd/2   0   -
B   75  159 dsadasd/2   0   +
B   78  852 dsadasd/1   0   -
C   12  789 dsadasd/1   0   +
C   91  546 dsadasd/2   0   -
A   87  52  dsadasd/2   0   +
A   52  15  dsadasd/1   0   -

TIA

Answer 1

awk：

$ awk  '{
    k=NR%2; a[k]=$4; b[k]=$0                     # store compare value and 
}                                                #      record for 0 and 1
!(NR%2) {                                        # on even we compare
    print b[(a[0]>a[1])] ORS b[(a[0]<=a[1])]     # and print the smaller first
}' file
A   35  74  dsadasd/1   0   +
A   95  74  dsadasd/2   0   -
B   78  852 dsadasd/1   0   -
B   75  159 dsadasd/2   0   +
C   12  789 dsadasd/1   0   +
C   91  546 dsadasd/2   0   -
A   52  15  dsadasd/1   0   - 
A   87  52  dsadasd/2   0   +

Answer 2

应该有一种更简单的方法，但这可行

$ awk '{c+=p!=$1; p=$1; print c "\t" $0}' file | sort -k1,1 -k5 | cut -f2-

A   35  74  dsadasd/1   0   +
A   95  74  dsadasd/2   0   -
B   78  852 dsadasd/1   0   -
B   75  159 dsadasd/2   0   +
C   12  789 dsadasd/1   0   +
C   91  546 dsadasd/2   0   -
A   52  15  dsadasd/1   0   -
A   87  52  dsadasd/2   0   +

根据第一个字段组创建一个组ID，首先按其排序，然后按另一个键字段排序；删除虚拟组ID。

Answer 3

尝试Perl ..请注意，这会保留输入中的空格

cloud.to_file('N.png')

带有输入

 perl -0777 -ne ' while( /(.+?)\n(.+?)\n/gms ) { $a=$1;$b=$2; (split(/\s+/,$a))[3] gt (split(/\s+/,$b))[3] ? print "$b\n$a\n" : print "$a\n$b\n"  }'

Answer 4

awk +排序

$ awk ' { $(NF+1)=int((NR+1)/2) } 1 ' angel.txt | sort -k7,7 -k4,4 | awk  ' {$NF=""}1 '
A 35 74 dsadasd/1 0 +
A 95 74 dsadasd/2 0 -
B 78 852 dsadasd/1 0 -
B 75 159 dsadasd/2 0 +
C 12 789 dsadasd/1 0 +
C 91 546 dsadasd/2 0 -
A 52 15 dsadasd/1 0 -
A 87 52 dsadasd/2 0 +

$ cat angel.txt
A   35  74  dsadasd/1   0   +
A   95  74  dsadasd/2   0   -
B   75  159 dsadasd/2   0   +
B   78  852 dsadasd/1   0   -
C   12  789 dsadasd/1   0   +
C   91  546 dsadasd/2   0   -
A   87  52  dsadasd/2   0   +
A   52  15  dsadasd/1   0   -

$

Answer 5

这应该适用于awk：

awk '{if(p==""){p=$0;p4=$4} 
      else{
          if(p4>$4){print $0"\n"p}
          else{print p"\n"$0};p=p4=""
     }}' file

以2行为一组对文本文件进行排序

5 个答案: