我是Python和Gurobi的新手,我正在阅读model.getAttr手册,并且我了解返回的参数是model.getAttr(attrname,objs = None)。
我不理解的是下面手册中提供的示例代码:
print(model.getAttr(“ Pi”,model.getConstrs()))
我的代码中attrname“ Pi”不在任何地方,为什么它仍然能够返回值?
请帮助!
try:
# Create a new model
m = Model("simplelp")
# Create variables
x1 = m.addVar(ub = 10, name="x1")
x2 = m.addVar(name="x2")
x3 = m.addVar(name="x3")
# Set objective
m.setObjective(x1 + 2 * x2 + 5 * x3, GRB.MAXIMIZE)
# Add constraint:
m.addConstr(-x1 + x2 + 3*x3 <= -5, "c0")
# Add constraint:
m.addConstr(x1 + 3*x2 - 7*x3 >= 10, "c1")
m.optimize()
# print optimal solutions
for v in m.getVars(): #m.getVars() retrieves all the variables in the model, contains v
print('%s %g' % (v.varName, v.x)) #v.varName returns name, v.x returns value
# print optimal value
print('Obj: %g' % m.objVal)
# print dual values to all constraints
print(m.getAttr("Pi", m.getConstrs()))
except GurobiError as e:
print('Error code ' + str(e.errno) + ": " + str(e))
except AttributeError:
print('Encountered an attribute error')
答案 0 :(得分:1)
我想你在误会什么。 “ Pi”是您使用m.addConstr()
方法创建的线性约束对象的属性。有关所有可用属性的概述,请参见here。
让我们考虑一下
from gurobipy import Model, GRB
# Create a new model
m = Model("simplelp")
# Create variables
x1 = m.addVar(ub = 10, name="x1")
x2 = m.addVar(name="x2")
x3 = m.addVar(name="x3")
# Set objective
m.setObjective(x1 + 2 * x2 + 5 * x3, GRB.MAXIMIZE)
# Add constraint:
con0 = m.addConstr(-x1 + x2 + 3*x3 <= -5, "c0")
# Add constraint:
con1 = m.addConstr(x1 + 3*x2 - 7*x3 >= 10, "c1")
m.optimize()
然后m.getConstrs()
返回一个包含所有约束对象的列表:
In [16]: print(m.getConstrs())
Out[16]: [<gurobi.Constr c0>, <gurobi.Constr c1>]
m.getAttr(attrname, objectslist)
为对象列表中的所有对象返回属性attrname的值:
In [18]: print(m.getAttr("Pi", [con0, con1]))
Out[18]: [2.0, 0.0]
In [19]: print(m.getAttr("Pi", m.getConstrs()))
Out[19]: [2.0, 0.0]
In [20]: print([con0.Pi, con1.Pi])
Out[20]: [2.0, 0.0]