Question

目标：我想基于由创建ID列排序的订阅ID列分组的Id列的第一个值来联接两个表。

情况：

Table1看起来像这样：

id  channel trx_date
123 organic 01/01/2019 05:00:00
234 direct  01/01/2019 05:01:00
987 add     01/01/2019 10:00:00
654 organic 01/01/2019 10:15:00

表2：

subscription_id id  os      created_at
sub890         123  mac     01/01/2019 05:00:01
sub890         234  mac     01/01/2019 05:01:01
sub111         987  windows 01/01/2019 10:00:01
sub111         654  mac     01/01/2019 10:20:01

我需要采用按预订ID分组的表2中的最早ID，并将其与表1进行内部连接。因此，在此示例中，我的输出将是

subscription_id id  os      created_at id       channel trx_date
sub890          123 mac     01/01/2019 05:00:01 organic 01/01/2019 05:00:00
sub111          987 windows 01/01/2019 10:00:01 add     01/01/2019 10:00:00

我尝试过的事情：我曾考虑过使用FIRST_VALUE，但对于如何连接它们却一无所知

SELECT t1.*, 
  t2.subscription_id,
  t2.os,
  t2.created_at, 
  FIRST_VALUE(t2.id) OVER (PARTITION BY t2.subscription_id ORDER BY t2.created_at ASC) as Min_Id
FROM table1 t1
INNER JOIN table2 t2 ON t1.id = t2.Min_id

小提琴信息：

CREATE TABLE table1
    ([id] varchar(13), [channel] varchar(50), [trx_date] Datetime)


INSERT INTO table1
VALUES
    ('123', 'organic', '2019-01-01 05:00:00'),
    ('234', 'direct', '2019-01-01 05:01:00'),
    ('987', 'add', '2019-01-01 10:00:00'),
    ('654', 'organic', '2019-01-01 10:15:00')

CREATE TABLE table2
    ([subscription_id] varchar(13),[id] varchar(13), [os] varchar(10), [created_at] Datetime)

INSERT INTO table2
VALUES
    ('sub890', '123', 'mac', '2019-01-01 05:00:01'),
    ('sub890', '234', 'mac', '2019-01-01 05:01:01'),
    ('sub111', '987', 'windows', '2019-01-01 10:00:01'),
    ('sub111', '654', 'mac', '2019-01-01 10:20:01')

由于ON子句，这显然不起作用。这种情况是否需要row_number函数加上叉号？有更好的方法吗？ FIRST_VALUE是使用错误的函数吗？

Answer 1

将apply与top (1)一起使用：

SELECT t1.*, t2.subscription_id, t2.id, t2.os, t2.created_at
FROM table1 t1 CROSS APPLY
     (SELECT TOP (1) t2.*
      FROM table2 t2 
      WHERE t1.id = t2.id
      ORDER BY t2.created_at ASC
     ) t2

Answer 2

您可以将row_number()与create_at日期一起使用，该日期将采用第一个ID

with cte as
(
select *,row_number() over(partition by subscription_id  order by created_at) rn
  from tabl2
) select cte.*,t1.* from cte 
       join table1 t1 on cte.id =t1.id
  where cte.rn=1

demo link

subscription_id id  os    created_at           rn   id  channel  trx_date
sub890          123 mac   01/01/2019 05:00:01   1   123 organic 01/01/2019 05:00:00
sub111          987 windows 01/01/2019 10:00:01 1   987 add     01/01/2019 10:00:00

如何根据组的第一个值联接两个表

2 个答案: