Question

我正在做一个writes in和reads from的Arduino（Uno）应用程序。我希望Arduino工作的方式仅在有数据时（如侦听器）读取，并在每次（定期使用delay写入）中进行。但是我不知道如何设置侦听器（或者是否有办法实现），因为我不希望delay影响reading。

 unsigned long timeDelay = 100;   //Some configurations
 String comand;
 char received;
 const int LED = 12;

void setup() {
  //start serial connection
  Serial.begin(9600);
  pinMode(LED, OUTPUT);   //LED is only a way that I know the Arduino is 
  digitalWrite(LED,LOW);  //reading correctly

}

void loop() {
  //How to separate this part--------------Reading from Serieal--------
  comand = "";
  while(Serial.available() > 0){    
    received = Serial.read();
    comand += received;
    if(comand == "DELAY"){            //Processing the command
      timeDelay = Serial.parseInt();
    }
  }
  if(comand == "Desliga"){            //Processing the command
     digitalWrite(LED,LOW);       //'Desliga' means 'turn on' in portuguese
  }
  else if(comand == "Liga"){          //Processing the command
    digitalWrite(LED,HIGH);       //'Liga' means 'turn off' in portuguese
  }
  //-------------------------------------------------------------------

  //From this other part-----------------Writing on Serial-------------
  int sensorValue = analogRead(A0);
  // print out the value you read:
  Serial.println(sensorValue);
  Serial.flush();
  delay(timeDelay);        // delay in between reads for stability
  //-------------------------------------------------------------------
}

OBS：我正在通过Java应用程序进行连接。因此，我可以在此处设置timeDelay。如果我输入timeDelay（ms）这样的1000，则我编写的一个命令（打开/关闭LED）将花费1秒的时间来处理。你们知道了吗？

有人解决吗？

Answer 1

我建议使用Arduino的任务管理器来运行您的模拟代码。

为此，我使用TaskAction。

您可以将模拟代码包装在一个函数中，并创建一个TaskAction对象：

void AnalogTaskFunction(TaskAction * pThisTask)
{
  int sensorValue = analogRead(A0);
  // print out the value you read:
  Serial.println(sensorValue);
  Serial.flush();
}

static TaskAction AnalogTask(AnalogTaskFunction, 100, INFINITE_TICKS);

并且在您的loop中，您可以运行任务并设置任务期限：

void loop() {
  //How to separate this part--------------Reading from Serieal--------
  comand = "";
  while(Serial.available() > 0){    
    received = Serial.read();
    comand += received;
    if(comand == "DELAY"){            //Processing the command
      AnalogTask.SetInterval(Serial.parseInt()); // Change the task interval
    }
  }
  if(comand == "Desliga"){            //Processing the command
     digitalWrite(LED,LOW);       //'Desliga' means 'turn on' in portuguese
  }
  else if(comand == "Liga"){          //Processing the command
    digitalWrite(LED,HIGH);       //'Liga' means 'turn off' in portuguese
  }

  AnalogTask.tick(); // Run the task
}

注意：可以使用Arduino的其他任务管理器，这只是我所熟悉的。您可能想探索其他人。

如何从串行总线（Arduino）读取中“分开”写入？

1 个答案: