我有两个类-主接口和子接口
有一个按钮会调出子界面,我试图直接(或几乎立即)获得子工具界面的输出,以便可以在按钮功能中使用它。
在我的代码中,如果执行以下操作:
除非我创建另一个函数get_results
,然后在其中正确显示self.my_dict
。
如此,我该如何编码,一旦按下“应用...”按钮,self.my_dict
将被更新而无需创建另一个函数?还是我只是想得太多?
class SubMenuWindow(QtGui.QWidget):
def __init__(self, menu_items, parent=None):
super(SubMenuWindow, self).__init__(parent)
self.my_lyt = QtGui.QVBoxLayout()
self.checked_options = []
self.sel = {}
for menu_name, submenu_name in menu_items.items():
# Set the main menu item name
self.groupbox = QtGui.QGroupBox(self)
self.groupbox.setTitle(menu_name)
self.groupbox.setLayout(QtGui.QVBoxLayout())
self.my_lyt.addWidget(self.groupbox)
if submenu_name:
sub_txt = [action for action in submenu_name]
for s in sub_txt:
sub_chk = QtGui.QCheckBox(s)
self.checked_options.append(sub_chk)
self.groupbox.layout().addWidget(sub_chk)
apply_tag_btn = QtGui.QPushButton('Apply to selected item')
apply_tag_btn.clicked.connect(self.get_checked_options)
self.my_lyt.addWidget(apply_tag_btn)
self.my_lyt.addStretch()
self.setLayout(self.my_lyt)
self.show()
def get_checked_options(self):
for f in self.checked_options:
if f.isChecked():
self.sel[f.parent().title()] = f.text()
class MainWin(QtGui.QWidget):
def __init__(self, parent=None):
super(MainWin, self).__init__(parent)
self.my_dict = {}
btnA = QtGui.QPushButton('Click Me')
btnA.clicked.connect(self.get_options)
btnB = QtGui.QPushButton('Get results')
btnB.clicked.connect(self.get_results)
layout = QtGui.QVBoxLayout()
layout.addWidget(btnA)
layout.addWidget(btnB)
self.setLayout(layout)
def get_options(self):
sample_dict = {'GrpA' : ['John', 'Zack'], 'GrpB' : ['Alice', 'Phan']}
self.subWin = SubMenuWindow(sample_dict)
# I had want to get the values from subWin as soon as User has hit on
# the 'Apply to selected item' button
self.my_dict = self.subWin.sel
print ">>> my dict values : ", self.my_dict
# do something else from here thereafter...
def get_results(self):
print self.subWin.sel
答案 0 :(得分:1)
创建新窗口不会阻塞,因此您的打印语句将在用户选择任何内容之前执行。您可以传递回调以在用户更改选择时通知调用窗口小部件。
例如:
class SubMenuWindow(QtWidgets.QWidget):
def __init__(self, menu_items, parent=None, callback=None):
super(SubMenuWindow, self).__init__(parent)
self.callback = callback
[...]
def get_checked_options(self):
for f in self.checked_options:
if f.isChecked():
self.sel[f.parent().title()] = f.text()
if self.callback:
self.callback()
并传递回调:
def get_options(self):
sample_dict = {'GrpA' : ['John', 'Zack'], 'GrpB' : ['Alice', 'Phan']}
self.subWin = SubMenuWindow(sample_dict, callback=self.get_results)
[...]
这样,只要用户单击get_result
中的Apply按钮,就会调用SubMenuWindow
方法。