Question

我已经完成了这段代码：

Num = int(input("Enter a large number: "))
Num2 = Num+10
print("If I added 10 to your number it would be:" , Num2)
print("The new number times 2 would be " , Num2*2)
count = 0
number = Num
while (number > 1):
  number = number//10
  count = count + 1
  i = 1
  for i in range(1,count+1):
  Num = Num+1*(10**i)
  i = i+1
print("adding one to every digit on your first number would be: " , Num + 1)

在此代码中，如果用户输入的值是整数9，我想结束它。我不知道怎么请帮助

如果输入9，则代码应刚刚结束，并且输出9无效

Answer 1

检查用户输入的数字是否为9并退出并显示一条消息。

Num = int(input("Enter a large number: "))    
if Num == 9:
   print("Invalid Input")
   exit()
else:
    Num2 = Num + 10
    print("If I added 10 to your number it would be:", Num2)
    print("The new number times 2 would be ", Num2 * 2)
    count = 0
    number = Num
    while (number > 1):
        number = number // 10
        count = count + 1
        i = 1
        for i in range(1, count + 1):
            Num = Num + 1 * (10 ** i)
        i = i + 1
    print("adding one to every digit on your first number would be: ", Num + 1)

或如果要检查输入中是否有9。

Num = str(input("Enter a large number: "))
if "9" in Num:
    print("Invalid Inputs")
    exit()

Answer 2

检查Num = 9是否执行os.exit(1)

Num = int(input("Enter a large number: "))
if Num == 9:
    exit()
Num2 = Num+10
print("If I added 10 to your number it would be:" , Num2)
print("The new number times 2 would be " , Num2*2)
count = 0
number = Num
while (number > 1):
  number = number//10
  count = count + 1
  i = 1
  for i in range(1,count+1):
  Num = Num+1*(10**i)
  i = i+1
print("adding one to every digit on your first number would be: " , Num + 1)

Answer 3

要排除所有包含数字9的值，请在将其转换为整数之前将其检查为字符串：

num_str = str(input("Enter a large number: "))
if "9" in num_str:
    print("Value contains a 9. This is invalid")
    exit()
num = int(num_str)

 ...

要仅排除值9，请检查该特定值：

num = int(input("Enter a large number: "))
if num == 9:
    print("Value is 9. This is invalid")
    exit()

...

Answer 4

只需执行

Num = int(input("Enter a large number: "))
if Num==9:
    print("9 is incorrect")
else:

    Num2 = Num+10
    print("If I added 10 to your number it would be:" , Num2)
    print("The new number times 2 would be " , Num2*2)
    count = 0
    number = Num
    while (number > 1):
      number = number//10
      count = count + 1
      i = 1
      for i in range(1,count+1):
      Num = Num+1*(10**i)
      i = i+1
    print("adding one to every digit on your first number would be: " , Num + 1)

希望有帮助

如果输入某个值，如何排除输入

4 个答案: