Question

我正在尝试根据所选ID排列数组例如，我有一个[{id:1}, {id:2}, {id:3}, {id:4}, {id:5}]数组所选数组为[3,5];输出将为[{id:1}, {id:3}, {id:5}, {id:2}, {id:4}]

我设法在[3,5]上进行了正确的排列，但是当我添加/更改所选数组的值时，问题并不一致

var aData = [{id:1},{id:2},{id:3},{id:4},{id:5}];
var selectedId = [3,5];


let firstArray;

selectedId.forEach(function(id) {
    let iIndex = selectedId.indexOf(id);
    if (iIndex === 0) {
       firstArray = iIndex;
    }   
    array_move(aData, id-1, selectedId[firstArray]-2);
});

function array_move(arr, old_index, new_index) {
    if (new_index >= arr.length) {
        var k = new_index - arr.length + 1;
        while (k--) {
           arr.push(undefined);
        }
    }
    arr.splice(new_index, 0, arr.splice(old_index, 1)[0]);
};

Answer 1

这会做到的。

    $string = 'false';
    if( $string == 'true'){
        $string = true;     
    }else if($string == 'false'){
        $string= false;     
    }

如果要保持selectedId数组的顺序，可以首先对selectedId数组应用reduce，以从aData中获取所选项。

然后将结果与selectedId中不存在的aData元素合并。

let output =aData.filter(obj => selectedId.indexOf(obj.id) > -1).concat(aData.filter(obj => selectedId.indexOf(obj.id) ==-1))
console.log(output)

Answer 2

filter，然后是concat：

var aData = [{id:1},{id:2},{id:3},{id:4},{id:5}];
var selectedId = [3,5];

aData = aData.filter(({ id }) => selectedId.includes(id)).concat(aData.filter(({ id }) => !selectedId.includes(id)));

console.log(aData);

根据所选ID排列对象数组

2 个答案: