将数组排列成基于重复字符串的对象数组

时间：2017-11-01 12:32:03

标签： javascript arrays

我有数组，我想安排在dot之前对同一个字符串的对象数组结构，我想创建一个对象数组结构，使其可编辑，所以我可以填充我的数组上的每个数据的值

pred_val

我如何安排成为对象数组结构

var arr = ["data",
        "data.cell",
        "data.cell.celltiming",
        "data.cell.celltiming.0",
        "data.cell.celltiming.1",
        "data.cell.earfcn",
        "data.cell.pci",
        "data.cell.rsrp",
        "data.cell.rsrp.0",
        "data.cell.rsrp.1",
        "data.cell.rsrp.2",
        "data.cell.rsrq",
        "data.cell.rsrq.0",
        "data.cell.rsrq.1",
        "data.cell.rsrq.2",
        "data.cell.sinr",
        "data.cell.sinr.0",
        "data.cell.sinr.1",
        "data.cells",
        "data.cells.0",
        "data.cells.0.ch",
        "data.cells.0.ecno",
        "data.cells.0.r99",
        "data.cells.0.rscp",
        "data.cells.0.sc",
        "data.cells.1",
        "data.cells.1.ch",
        "data.cells.1.ecno",
        "data.cells.1.r99",
        "data.cells.1.rscp",
        "data.cells.1.sc",
        "data.cells.2",
        "data.cells.2.ch",
        "data.cells.2.ecno",
        "data.cells.2.r99",
        "data.cells.2.rscp",
        "data.cells.2.sc",
        "data.cells.3",
        "data.cells.3.ch",
        "data.cells.3.ecno",
        "data.cells.3.r99",
        "data.cells.3.rscp",
        "data.cells.3.sc",
        "data.id",
        "data.mac",
        "data.plmn",
        "data.rssi",
        "data.time",
        "deviceID",
        "time"]

我想创建一个对象数组，以便我可以填充每个键的值

1 个答案:

答案 0 :(得分：0)

我使用了以下内容：

  1. Array.prototype.reduce()，累积在空对象{}上，
  2. ref对象的引用（accumulator）
  3. String.prototype.split()从数组中的当前字符串中提取单个key s（子字符串），

  4. 迭代key以沿着key“链”前进，

    一个。如果key对象中尚不存在accumulator，请在该密钥上创建一个对象，即if (!ref[key]) ref[key] = {}

    湾通过重新设置引用（accumulator）继续遍历ref对象，即ref = ref[key]

  5. 移至原始数组中的下一个字符串

    6. var arr = ["data",
  "data.cell",
  "data.cell.celltiming",
  "data.cell.celltiming.0",
  "data.cell.celltiming.1",
  "data.cell.earfcn",
  "data.cell.pci",
  "data.cell.rsrp",
  "data.cell.rsrp.0",
  "data.cell.rsrp.1",
  "data.cell.rsrp.2",
  "data.cell.rsrq",
  "data.cell.rsrq.0",
  "data.cell.rsrq.1",
  "data.cell.rsrq.2",
  "data.cell.sinr",
  "data.cell.sinr.0",
  "data.cell.sinr.1",
  "data.cells",
  "data.cells.0",
  "data.cells.0.ch",
  "data.cells.0.ecno",
  "data.cells.0.r99",
  "data.cells.0.rscp",
  "data.cells.0.sc",
  "data.cells.1",
  "data.cells.1.ch",
  "data.cells.1.ecno",
  "data.cells.1.r99",
  "data.cells.1.rscp",
  "data.cells.1.sc",
  "data.cells.2",
  "data.cells.2.ch",
  "data.cells.2.ecno",
  "data.cells.2.r99",
  "data.cells.2.rscp",
  "data.cells.2.sc",
  "data.cells.3",
  "data.cells.3.ch",
  "data.cells.3.ecno",
  "data.cells.3.r99",
  "data.cells.3.rscp",
  "data.cells.3.sc",
  "data.id",
  "data.mac",
  "data.plmn",
  "data.rssi",
  "data.time",
  "deviceID",
  "time"
]
var obj = arr.reduce((accumulator, currentValue, currentIndex) => {
  let ref = accumulator;
  currentValue.split(".").forEach(key => {
    if (!ref[key]) ref[key] = {}
    ref = ref[key];
  })
  return accumulator;
}, {})

console.log(JSON.stringify(obj, null, "\t"));

    这让你大部分时间都可以。现在你需要做的就是：

    1. 遍历对象（第一遍），用空字符串替换空对象，然后

      arr.forEach(chain => { // first pass, change empty objects to empty strings
  let ref = obj;
  chain.split(".").forEach(key => {
    if (Object.keys(ref[key]).length === 0) {
      ref[key] = ''
    } else {
      ref = ref[key]
    }
  })
})

    2. 遍历对象（第二遍），检查对象的所有键是否为数字且所有值都是空字符串，并用键数组替换此对象。

      function keysAreNumbersAndValuesAreEmptyStrings(object) {
  let entries = Object.entries(object);
  for (let i = 0; i < entries.length; i++) {
    let key = entries[i][0], value = entries[i][1];
    if(isNaN(Number(key)) || typeof value !== "string" || value.length !== 0) return false;
  }
  return true;
}

arr.forEach(chain => { // second pass, change objects whose keys are numbers to an array of those keys
  let ref = obj;
  chain.split(".").forEach(key => {
    if (typeof ref[key] === "object" && keysAreNumbersAndValuesAreEmptyStrings(ref[key])) {
      ref[key] = Object.keys(ref[key]).map(val => Number(val));
    } else {
      ref = ref[key]
    }
  })
})

      3. 完整解决方案：https://jsfiddle.net/s2attatz/1/ 

      var arr = ["data",
  "data.cell",
  "data.cell.celltiming",
  "data.cell.celltiming.0",
  "data.cell.celltiming.1",
  "data.cell.earfcn",
  "data.cell.pci",
  "data.cell.rsrp",
  "data.cell.rsrp.0",
  "data.cell.rsrp.1",
  "data.cell.rsrp.2",
  "data.cell.rsrq",
  "data.cell.rsrq.0",
  "data.cell.rsrq.1",
  "data.cell.rsrq.2",
  "data.cell.sinr",
  "data.cell.sinr.0",
  "data.cell.sinr.1",
  "data.cells",
  "data.cells.0",
  "data.cells.0.ch",
  "data.cells.0.ecno",
  "data.cells.0.r99",
  "data.cells.0.rscp",
  "data.cells.0.sc",
  "data.cells.1",
  "data.cells.1.ch",
  "data.cells.1.ecno",
  "data.cells.1.r99",
  "data.cells.1.rscp",
  "data.cells.1.sc",
  "data.cells.2",
  "data.cells.2.ch",
  "data.cells.2.ecno",
  "data.cells.2.r99",
  "data.cells.2.rscp",
  "data.cells.2.sc",
  "data.cells.3",
  "data.cells.3.ch",
  "data.cells.3.ecno",
  "data.cells.3.r99",
  "data.cells.3.rscp",
  "data.cells.3.sc",
  "data.id",
  "data.mac",
  "data.plmn",
  "data.rssi",
  "data.time",
  "deviceID",
  "time"
]
var obj = arr.reduce((accumulator, currentValue, currentIndex) => {
  let ref = accumulator;
  currentValue.split(".").forEach(key => {
    if (!ref[key]) ref[key] = {}
    ref = ref[key];
  })
  return accumulator;
}, {})

    arr.forEach(chain => { // first pass, change empty objects to empty strings
      let ref = obj;
      chain.split(".").forEach(key => {
        if (Object.keys(ref[key]).length === 0) {
          ref[key] = ''
        } else {
          ref = ref[key]
        }
      })
    })

    function keysAreNumbersAndValuesAreEmptyStrings(object) {
      let entries = Object.entries(object);
      for (let i = 0; i < entries.length; i++) {
        let key = entries[i][0], value = entries[i][1];
        if(isNaN(Number(key)) || typeof value !== "string" || value.length !== 0) return false;
      }
      return true;
    }

    arr.forEach(chain => { // second pass, change objects whose keys are numbers to an array of those keys
      let ref = obj;
      chain.split(".").forEach(key => {
        if (typeof ref[key] === "object" && keysAreNumbersAndValuesAreEmptyStrings(ref[key])) {
          ref[key] = Object.keys(ref[key]).map(val => Number(val));
        } else {
          ref = ref[key]
        }
      })
    })

console.log(JSON.stringify(obj, null, "\t"));

      /*
{
  "data": {
    "cell": {
      "celltiming": [
        0,
        1
      ],
      "earfcn": "",
      "pci": "",
      "rsrp": [
        0,
        1,
        2
      ],
      "rsrq": [
        0,
        1,
        2
      ],
      "sinr": [
        0,
        1
      ]
    },
    "cells": {
      "0": {
        "ch": "",
        "ecno": "",
        "r99": "",
        "rscp": "",
        "sc": ""
      },
      "1": {
        "ch": "",
        "ecno": "",
        "r99": "",
        "rscp": "",
        "sc": ""
      },
      "2": {
        "ch": "",
        "ecno": "",
        "r99": "",
        "rscp": "",
        "sc": ""
      },
      "3": {
        "ch": "",
        "ecno": "",
        "r99": "",
        "rscp": "",
        "sc": ""
      }
    },
    "id": "",
    "mac": "",
    "plmn": "",
    "rssi": "",
    "time": ""
  },
  "deviceID": "",
  "time": ""
}
*/
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