public class MovingBagView extends View {
private Bitmap bag[] = new Bitmap[2];
private int bagX;
private int bagY = 1000;
private int bagSpeed;
private Boolean touch = false;
private int canvasWidth, canvasHeight;
private Bitmap backgroundImage;
private Paint scorePaint = new Paint();
private Bitmap life[] = new Bitmap[2];
public MovingBagView(Context context) {
super(context);
bag[0] = BitmapFactory.decodeResource(getResources(), R.drawable.bag1);
bag[1] = BitmapFactory.decodeResource(getResources(), R.drawable.bag2);
backgroundImage = BitmapFactory.decodeResource(getResources(), R.drawable.background);
scorePaint.setColor(Color.BLACK);
scorePaint.setTextSize(40);
scorePaint.setTypeface(Typeface.DEFAULT_BOLD);
scorePaint.setAntiAlias(true);
life[0] = BitmapFactory.decodeResource(getResources(), R.drawable.heart);
life[1] = BitmapFactory.decodeResource(getResources(), R.drawable.heart_grey);
bagX = 10;
}
@Override
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
canvasWidth = canvas.getWidth();
canvasHeight = canvas.getHeight();
canvas.drawBitmap(backgroundImage, 0, 0, null);
int minBagX = bag[0].getWidth();
int maxBagX = canvasWidth - bag[0].getWidth() * 3;
bagX = bagX + bagSpeed;
if (bagX < minBagX) {
bagX = minBagX;
}
if (bagX < maxBagX) {
bagX = maxBagX;
}
bagSpeed = bagSpeed + 2;
if (touch) {
canvas.drawBitmap(bag[1], bagX, bagY, null);
}
else {
canvas.drawBitmap(bag[0], bagX, bagY, null);
}
canvas.drawText("Score : ", 20, 60, scorePaint);
canvas.drawBitmap(life[0], 500, 10, null);
canvas.drawBitmap(life[0], 570, 10, null);
canvas.drawBitmap(life[0], 640, 10, null);
}
@Override
public boolean onTouchEvent(MotionEvent event) {
if (event.getAction() == MotionEvent.ACTION_DOWN) {
touch = true;
bagSpeed = -12;
}
return true;
}
}
我可以点击屏幕上的将该对象向左移动,而我点击的次数越多,它应该向左移动的越远。但是,问题在于该对象向右移动太多,并离开了屏幕。我希望它停在边缘,因此它仍在屏幕上可见。此外,对象位于屏幕的中央底部,如何将其放置在屏幕的左下角?您可以通过下面的GIF查看其工作原理。
答案 0 :(得分:2)
此条件永远不会应用于您提供的代码。它继续超过最大值。
if (bagX < maxBagX) {
bagX = maxBagX;
}
它应该像这样:
if (bagX >= maxBagX) {
bagX = maxBagX;
}
并且maxBagX值应为canvasWidth - bag[0].getWidth()
,以便获得袋子本身的右边缘。 (除非您出于不同的原因使用了3次乘法,否则这应该是解决方案。)
答案 1 :(得分:0)
使用线性,相对或约束条件创建布局的对象,然后使用该对象使用
获取屏幕宽度object.getWidth();
答案 2 :(得分:0)
我这样做了// // maintainoffscreen函数将保持不移出屏幕的路径,并返回true,否则,如果路径未与任何一侧碰撞,则将返回false,您可以通过设置来移动路径偏移量。
private boolean maintainOffScreen(Path path, float px, float py){
boolean done = true;
RectF rectF = new RectF();
path.computeBounds(rectF,true);
float l = getPathWidth(path) - rectF.right;
float r = getPathWidth(path) + rectF.left;
float t = getPathHeight(path) - rectF.bottom;
float b = getPathHeight(path)+ rectF.top;
if(l < (-1) && r < getWidth() && b < getHeight() && t< (-1)){
//if path does not collide to any side//you can move your path here as well
//by setting Path.offset(px,py)
done = false;
offScreen = OffScreen.NOOFF; //im using these as enum according to my need,
//as this is saving which side of screen collides
}
else if(l >= (-1)){
path.offset(px+(l),py);
offScreen = OffScreen.LEFT;
offscrenn_xl = 1;
done = true;
}
else if(r >= getWidth()){
float s = getWidth() - r;
path.offset(px+(s),py);
offScreen = OffScreen.RIGHT;
offscrenn_xr = s;
done = true;
}
else if(b >= getHeight()){
float s = getHeight() - b;
path.offset(px,py+s);
offScreen = OffScreen.BOTTOM;
offscrenn_yb = s;
done = true;
}
else if(t >= (-1)){
path.offset(px,py+(t));
offScreen = OffScreen.TOP;
offscrenn_yt = t;
done = true;
}
return done;
}
对px,py感到困惑?这是手指相对于路径的运动
`
final float px = event.getX() - this.startX;
final float py = event.getY() - this.startY;
if(!maintainOffScreen(path,px,py)){path.offset(px,py); }` //you should call
//this function here ,this will move your path to finger if there is no collision.
//and donot forgot to set the startx,and starty yo new positon like this
this.startX = event.getX();
this.startY = event.getY();