Question

在Python 3和熊猫中，我有一个带有单词列表列的数据框“ proposicoes”。该列名为“ ementa_token”

我想从“ ementa_token”列中总结出来。每行都有一个单词列表：

proposicoes[proposicoes['id'] == '465465']['ementa_token'].iloc[0]
['Comunica',
 'Excelentíssimo',
 'Senhor',
 'Presidente',
 'República',
 'sanção',
 'projeto',
 'lei',
 'Institui',
 'Fundo',
 'Nacional',
 'Idoso',
 'autoriza',
 'deduzir',
 'imposto',
 'renda',
 'devido',
 'pessoas',
 'físicas',
 'jurídicas',
 'doações',
 'efetuadas',
 'Fundos',
 'Municipais',
 'Estaduais',
 'Nacional',
 'Idoso',
 'altera',
 'Lei',
 'nº',
 '9250',
 '26',
 'dezembro',
 '1995',
 'restitui',
 'arquivo',
 'Congresso',
 'Nacional',
 'dois',
 'autógrafos',
 'texto',
 'ora',
 'convertido',
 'Lei',
 'nº',
 '12213',
 '20',
 'janeiro',
 '2010']

我尝试过这种方式：

from wordcloud import WordCloud
import matplotlib.pyplot as plt
%matplotlib inline

wordcloud = WordCloud(width=800, height=400).generate(proposicoes['ementa_token'])
plt.figure( figsize=(30,20) )
plt.imshow(wordcloud)
plt.axis("off")
plt.show()

我遇到了这个错误：

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-18-c072e91a9fe7> in <module>
----> 1 wordcloud = WordCloud(width=800, height=400).generate(proposicoes['ementa_token'])
      2 plt.figure( figsize=(30,20) )
      3 plt.imshow(wordcloud)
      4 plt.axis("off")
      5 plt.show()

c:\users\reinaldo\documents\code\palavras\lib\site-packages\wordcloud\wordcloud.py in generate(self, text)
    603         self
    604         """
--> 605         return self.generate_from_text(text)
    606 
    607     def _check_generated(self):

c:\users\reinaldo\documents\code\palavras\lib\site-packages\wordcloud\wordcloud.py in generate_from_text(self, text)
    584         self
    585         """
--> 586         words = self.process_text(text)
    587         self.generate_from_frequencies(words)
    588         return self

c:\users\reinaldo\documents\code\palavras\lib\site-packages\wordcloud\wordcloud.py in process_text(self, text)
    551         regexp = self.regexp if self.regexp is not None else r"\w[\w']+"
    552 
--> 553         words = re.findall(regexp, text, flags)
    554         # remove stopwords
    555         words = [word for word in words if word.lower() not in stopwords]

c:\users\reinaldo\documents\code\palavras\lib\re.py in findall(pattern, string, flags)
    221 
    222     Empty matches are included in the result."""
--> 223     return _compile(pattern, flags).findall(string)
    224 
    225 def finditer(pattern, string, flags=0):

TypeError: expected string or bytes-like object

这是否意味着代码没有读取每一行列表中的单词？拜托，有人知道怎么做吗？

Answer 1

TypeError很清楚，WordCloud期望字符串不是Series。合并列中的列表，然后加入，

wordcloud = WordCloud(width=800, height=400).generate(' '.join(proposicoes['ementa_token'].sum())

选项2：

data = ' '.join(np.concatenate(df.col2))
wordcloud = WordCloud(width=800, height=400).generate(' '.join(data)

如何在具有列表的数据框中形成单词云？

1 个答案: