Question

我认为这很简单，但我很挣扎（可能是星期五的大脑）

我有一张桌子：

Staff      department     job_date       job             Hours
---------------------------------------------------------------
Chris      Software       2011-03-02     Writing Code    3
Chris      Software       2011-03-04     Holiday         7
Bob        QA             2011-03-02     Testing         4
Frank      Design         2011-03-11     Meeting         1

现在，我需要一个查询，根据工作字段中的最新情况，按天“分组”结果，即..所以我得到每个员工在工作和假期时花费的小时数：

结果集：

Staff          Worked Hours       Holiday Hours  Department
---------------------------------------------------------------
Chris           3                  7              Software
Bob             4                  0              QA
Frank           1                  0              Design
---------------------------------------------------------------
Total           8                  7

感谢您提供任何帮助！

克里斯

Answer 1

SELECT  department, staff,
        SUM(IF(job = 'Holiday', 0, hours)) AS work_hours,
        SUM(IF(job = 'Holiday', hours, 0)) AS holiday_hours
FROM    mytable
GROUP BY
        department, staff WITH ROLLUP

Answer 2

select staff,
       sum(case when job='holiday' then 0 else hours end) `Worked Hours`,
       sum(case when job='holiday' then hours else 0 end) `Holiday Hours`,
       department
from tbl
group by staff, department

分组查询（Pivot样式？）

2 个答案: