Question

我尝试了PIVOT方法和CASE WHEN，但我还没想出如何从我的表格中获得此结果。

这就是我们所需要的：

personnel_id  SATURDAY SUNDAY  MONDAY   TUESDAY   WEDNESDAY THURSDAY  FRIDAY
Juan Jose       OFF     OFF     6-2        6- 2      OFF      OFF      6-2

来自这些表格：

[TABLES FROM SQL SERVER][1]

到目前为止，我有：

SELECT  
    personnel_name, 
    CASE WHEN day_name = 'saturday' then entrada END AS SAT,
    CASE WHEN day_name = 'sunday' then entrada END AS SUN,
    CASE WHEN day_name = 'monday' then entrada END AS MON,
    CASE WHEN day_name = 'tuesday' then entrada END AS TUE,
    CASE WHEN day_name = 'wednesday' then entrada END AS WED,
    CASE WHEN day_name = 'thursday' then entrada END AS THUR,
    CASE WHEN day_name = 'friday' then entrada END AS FRI
FROM
   (SELECT 
        personnel_name, tbl_shifts.entrada, tbl_days.day_name
    FROM 
        tbl_personnel_weekshift 
    INNER JOIN 
        tbl_personnel ON tbl_personnel_weekshift.personnel_id = tbl_personnel.personnel_id
    INNER JOIN 
        tbl_shifts ON tbl_personnel_weekshift.shift_id = tbl_shifts.shift_id
    INNER JOIN 
        tbl_days ON tbl_personnel_weekshift.day_id = tbl_days.day_id) AS IIIPO;

返回这些结果：

RESULTS

Juan Jose Moreno OFF    NULL    NULL NULL   NULL    NULL    NULL
Juan Jose Moreno NULL   OFF     NULL NULL   NULL    NULL    NULL
Juan Jose Moreno NULL   NULL    6-2  NULL   NULL    NULL    NULL
Juan Jose Moreno NULL   NULL    NULL 6-2    NULL    NULL    NULL
Juan Jose Moreno NULL   NULL    NULL NULL   OFF     NULL    NULL
Juan Jose Moreno NULL   NULL    NULL NULL   NULL    OFF     NULL
Juan Jose Moreno NULL   NULL    NULL NULL   NULL    NULL    6-2

我需要找到一个好的方法，或者找到一种只在一行中分组的方法，并摆脱空值。

感谢您的时间和精力，伙计们

Answer 1

我认为你只想要条件聚合：

SELECT personnel_name, 
       MAX(CASE WHEN day_name = 'saturday' then entrada END) AS SAT,
       MAX(CASE WHEN day_name = 'sunday' then entrada END) AS SUN,
       MAX(CASE WHEN day_name = 'monday' then entrada END) AS MON,
       MAX(CASE WHEN day_name = 'tuesday' then entrada END) AS TUE,
       MAX(CASE WHEN day_name = 'wednesday' then entrada END) AS WED,
       MAX(CASE WHEN day_name = 'thursday' then entrada END) AS THUR,
       MAX(CASE WHEN day_name = 'friday' then entrada END) AS FRI
FROM (SELECT personnel_name, tbl_shifts.entrada, tbl_days.day_name
      FROM tbl_personnel_weekshift INNER JOIN
           tbl_personnel
           ON tbl_personnel_weekshift.personnel_id = tbl_personnel.personnel_id INNER JOIN
           tbl_shifts
           ON tbl_personnel_weekshift.shift_id = tbl_shifts.shift_id INNER JOIN
           tbl_days
           ON tbl_personnel_weekshift.day_id = tbl_days.day_id
     ) IIIPO
GROPU BY personnel_name;

SQL SERVER QUERY与PIVOT和GROUPED INNER JOIN

1 个答案: