Question

我在SQL中具有以下数据：

date    code    price
2019-01-22  HDBUY   18.99
2019-01-22  HDRENT  3.99
2019-01-22  SDBUY   13.99
2019-01-22  SDRENT  2.99

这将如何完成？目前我正在做：

SELECT
date,
CASE WHEN s.code = <all the differe case statements>
FROM table
GROUP BY date

但这给了我除第一个以外的所有空条目：

date    HDBUY   SDBUY   HDRENT  SDRENT
2019-01-22  18.99   NULL    NULL    NULL

Answer 1

以下查询应为您提供结果：

select
  date,
  sum(case when code = 'HDBUY' then price end) as hdbuy,
  sum(case when code = 'HDRENT' then price end) as hdrent,
  sum(case when code = 'SDBUY' then price end) as sdbuy,
  sum(case when code = 'SDRENT' then price end) as sdrent
from my_table
group by date

具有非空条目的数据透视查询

1 个答案: