我有以下查询:
SELECT * FROM
(
SELECT unix_timestamp, input_raw, tag_id
from [200030].[dbo].inputs
WHERE inputs.date_time > dateadd(day,-1,getdate())
AND
(tag_id = 92164 or tag_id = 92149)
) src
pivot
(
max(input_raw)
FOR tag_id IN ([92164], [92149])
) piv
ORDER by unix_timestamp DESC
这很棒,很有效。它给了我结果:
但是,我希望查询能为我做一件事。
每当存在'NULL'结果时,我希望查询将'NULL'替换为列中的最后一个'non-NULL'值。
例如,列'92164'中看到的第一个NULL将替换为'211'。
此外,有可能会有几个'NULL'一行,所以查询需要继续上升,直到找到无NULL为止。
我已经能够通过php实现这一目标。将结果放入2D关联数组并运行找到空值的函数然后循环查找最后一个非NULL,但我真的想在SQL中尽可能地执行此操作。
我更愿意使用while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC)){
//code
}
方法比分配多个数组。
任何帮助?
谢谢
// EDIT
忘记添加,这仅适用于空值以上的任何非空值。例如,如果第一行为NULL,则可以接受。
答案 0 :(得分:2)
您可以将您的透视查询放在CTE中,并在计算出要显示的值时重复使用CTE。您的数据仅在第一列中具有空值,但此处是处理两列中的空值的版本。
WITH C AS
(
SELECT *
FROM (
SELECT unix_timestamp, input_raw, tag_id
FROM inputs
WHERE date_time > dateadd(day,-1,getdate()) AND
(tag_id = 92164 OR tag_id = 92149)
) src
PIVOT
(
MAX(input_raw)
FOR tag_id IN ([92164], [92149])
) piv
)
SELECT C1.unix_timestamp,
(
SELECT TOP(1) C2.[92164]
FROM C AS C2
WHERE C1.unix_timestamp <= C2.unix_timestamp AND
C2.[92164] IS NOT NULL
ORDER BY C2.unix_timestamp
) AS [92164],
(
SELECT TOP(1) C2.[92149]
FROM C AS C2
WHERE C1.unix_timestamp <= C2.unix_timestamp AND
C2.[92149] IS NOT NULL
ORDER BY C2.unix_timestamp
) AS [92149]
FROM C AS C1
ORDER by C1.unix_timestamp DESC;
如果遇到性能问题,将CTE结果存储在具有有用聚簇键索引的临时表中可能会更快。
CREATE TABLE #C
(
unix_timestamp int PRIMARY KEY,
[92164] int,
[92149] int
);
INSERT INTO #C
SELECT *
FROM (
SELECT unix_timestamp, input_raw, tag_id
FROM inputs
WHERE date_time > dateadd(day,-1,getdate()) AND
(tag_id = 92164 OR tag_id = 92149)
) src
PIVOT
(
MAX(input_raw)
FOR tag_id IN ([92164], [92149])
) piv;
SELECT C1.unix_timestamp,
(
SELECT TOP(1) C2.[92164]
FROM #C AS C2
WHERE C1.unix_timestamp <= C2.unix_timestamp AND
C2.[92164] IS NOT NULL
ORDER BY C2.unix_timestamp
) AS [92164],
(
SELECT TOP(1) C2.[92149]
FROM #C AS C2
WHERE C1.unix_timestamp <= C2.unix_timestamp AND
C2.[92149] IS NOT NULL
ORDER BY C2.unix_timestamp
) AS [92149]
FROM #C AS C1
ORDER by C1.unix_timestamp DESC;
DROP TABLE #C;
答案 1 :(得分:0)
您可以使用&#34;运行总计&#34;计算方法detailed here。创建临时表或表变量以保存数据透视查询的结果,并使用额外的列来保存92164列的最后一个非空值。我不能让SQLFiddle这样做,但它适用于我的机器(着名的遗言)
CREATE TABLE #pivot_results ([unix_timestamp] int, [92164] int, [92149] int)
INSERT INTO #pivot_results ([unix_timestamp], [92164], [92149])
VALUES
(1361893407, NULL, 294),
(1361893218, 207, 294),
(1361893108, NULL, 292),
(1361892807, 211, 292),
(1361892799, NULL, 292)
CREATE TABLE #update_me
([unix_timestamp] int, [92164] int, [92149] int, last_not_null_92164 int)
DECLARE @last_not_null_92164 INT = NULL;
INSERT INTO #update_me([unix_timestamp], [92164], [92149], last_not_null_92164)
SELECT unix_timestamp, [92164], [92149], NULL
FROM #pivot_results
ORDER BY unix_timestamp DESC
UPDATE #update_me
SET @last_not_null_92164 = last_not_null_92164 = ISNULL([92164],@last_not_null_92164)
FROM #update_me
SELECT
unix_timestamp
,last_not_null_92164 AS [92164]
,[92149]
FROM #update_me
ORDER BY unix_timestamp DESC