我有一个有4条车道的游戏-船要成对从上到下移动，而您的角色（海豚）应该通过按A和D键来避开它们。我将第一艘船的起点定为Y -100，将第二艘船的起点定为Y -450。当您运行游戏时，船之间的距离会随着它们每次在顶部再次产卵而变化。为什么会这样呢？据我了解，两船之间的距离应始终保持在350。有人可以帮我吗？
MEGA下载图像和SFX：https://mega.nz/fm/zHohiSJD
import pygame
import random
import os
os.environ['SDL_VIDEO_WINDOW_POS'] = "%d, %d" % (0, 20) # positions the game tab to the top left portion of the monitor
pygame.init() # initializes pygame
pygame.display.set_caption("Biomagnification ")
SIZE = W, H = 400, 700 # determining the screen size of the game
screen = pygame.display.set_mode(SIZE) # creating a display surface
clock = pygame.time.Clock() # creating a clock
# RGB colours
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)
BACKGROUND = (94, 194, 222)
STRIPE = (60, 160, 190)
WHITE = (255, 255, 255)
BLACK = (0, 0, 0)
# variables
x1 = 30 # desired X position for the left dolphin/hitbox
x2 = 330 # desired X position for the right dolphin/hitbox
lane1 = 30
lane2 = 130
lane3 = 230
lane4 = 330
y = 530 # desired y value of the hitbox
width, height = (40, 64) # width and height of the hitbox
toggle1 = 0 # toggle for left dolphin
toggle2 = 0 # toggle for right dolphin
target_x1 = 30
target_x2 = 330
vel_x = 10 # speed at which the dolphins move
def drawScene():
screen.fill(BACKGROUND) # fills the background with the colour ((94, 194, 222)
pygame.draw.polygon(screen, STRIPE,
((200, 700), (300, 700), (400, 600), (400, 500))) # draws the different coloured stripes
pygame.draw.polygon(screen, STRIPE, ((0, 700), (100, 700), (400, 400), (400, 300)))
pygame.draw.polygon(screen, STRIPE, ((0, 500), (0, 600), (400, 200), (400, 100)))
pygame.draw.polygon(screen, STRIPE, ((0, 300), (0, 400), (400, 0), (300, 0)))
pygame.draw.polygon(screen, STRIPE, ((0, 100), (0, 200), (200, 0), (100, 0)))
pygame.draw.line(screen, WHITE, (100, 0), (100, 700), 2) # draws the white separating lines in the background
pygame.draw.line(screen, WHITE, (200, 0), (200, 700), 6)
pygame.draw.line(screen, WHITE, (300, 0), (300, 700), 2)
# dolphin spritesheet
mainsheet = pygame.image.load("mainsheetSmall.png").convert() # load in the spritesheet
sheetSize = mainsheet.get_size() # gets the size of the spritesheet
horiz_cells = 36 # number of horizontal frames/cells in the spritesheet
vert_cells = 1 # number of vertical frames/cells in the spritesheet
cell_width = int(sheetSize[0] / horiz_cells) # determining the width of each cell
cell_height = int(sheetSize[1] / vert_cells) # determing the height of each cell
cellList = [] # creates a list for all the cells
for vert in range(0, sheetSize[1], cell_height):
for horz in range(0, sheetSize[0], cell_width):
surface = pygame.Surface((cell_width, cell_height))
surface.blit(mainsheet, (0, 0),
(horz, vert, cell_width, cell_height))
colorkey = surface.get_at((0, 0)) # gets the colour at O, 0 (white)
surface.set_colorkey(colorkey) # removes all the white from the spritesheet, making the background transparent
cellList.append(surface) # appends to the list of cells (cellList)
cellPosition = 0 # determines which frame is playing. Starts at 0
船上代码
# boat
boatSpeed = 10
boat = pygame.image.load("boat.png").convert_alpha()
boatX = random.choice([lane1, lane2, lane3, lane4])
if boatX == lane1:
boatX2 = random.choice([lane3, lane4])
elif boatX == lane2:
boatX2 = random.choice([lane3, lane4])
else:
boatX2 = random.choice([lane1, lane2])
boatY = -100
boatX3 = random.choice([lane1, lane2, lane3, lane4])
if boatX3 == lane1:
boatX4 = random.choice([lane3, lane4])
elif boatX3 == lane2:
boatX4 = random.choice([lane3, lane4])
else:
boatX4 = random.choice([lane1, lane2])
boatY2 = -450
。
# main loop
while True:
clock.tick(60) # makes the game tick 60 frames per second
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_ESCAPE: # detects if the user presses the ESC key
pygame.quit()
elif event.key == pygame.K_a: # detects if the user presses the A key
pygame.mixer.music.load('percussiveHit.mp3')
pygame.mixer.music.play()
toggle1 += 1 # adds 1 to toggle1
if toggle1 % 2 == 1: # if toggle1 mod 2 equals 1
target_x1 += 100 # add 100 to the target position
else:
target_x1 -= 100 # if toggle1 mod 2 does not equal 1, subtract 100 from the target position making it the original of 30
elif event.key == pygame.K_d: # detects if the user presses the D key
pygame.mixer.music.load('percussiveHit.mp3')
pygame.mixer.music.play()
toggle2 += 1 # adds 1 to toggle2
if toggle2 % 2 == 1: # if toggle2 mod 2 equals 1
target_x2 -= 100 # subtract 100 the to target position
else:
target_x2 += 100 # if toggle2 mod 2 does not equal 1, add 100 to the target position making it the original of 330
if x1 < target_x1:
x1 = min(x1 + vel_x, target_x1)
else:
x1 = max(x1 - vel_x, target_x1)
if x2 < target_x2:
x2 = min(x2 + vel_x, target_x2)
else:
x2 = max(x2 - vel_x, target_x2)
if cellPosition < len(cellList) - 1:
cellPosition += 1
else:
cellPosition = 0
船上第二段代码
boatY += boatSpeed
if boatY > H:
boatX == random.choice([lane1, lane2, lane3, lane4])
if boatX == lane1:
boatX2 == random.choice([lane3, lane4])
elif boatX == lane2:
boatX2 == random.choice([lane3, lane4])
else:
boatX2 == random.choice([lane1, lane2])
boatY = -100
boatY2 += boatSpeed
if boatY2 > H:
boatX3 == random.choice([lane1, lane2, lane3, lane4])
if boatX3 == lane1:
boatX4 == random.choice([lane3, lane4])
elif boatX3 == lane2:
boatX4 == random.choice([lane3, lane4])
else:
boatX3 == random.choice([lane3, lane4])
boatY2 = -450
# pygame.draw.rect(screen, GREEN, (x1, y, width, height)) # hitbox of left dolphin
pygame.draw.rect(screen, GREEN, (x2, y, width, height)) # hitbox of right dolphin
drawScene() # draws the scene (background, lane-lines, etc)
# players
screen.blit(cellList[cellPosition], (x1 + 4, y - 1)) # the left dolphin
screen.blit(cellList[cellPosition], (x2 + 4, y - 1)) # the right dolphin
screen.blit(boat, (boatX, boatY))
screen.blit(boat, (boatX2, boatY))
screen.blit(boat, (boatX3, boatY2))
screen.blit(boat, (boatX4, boatY2))
# screen.blit(boat, (boatX5, boaY3))
# screen.blit(boat, (boatX6, boatY4))
pygame.display.update()
答案 0 :(得分：0)
boat-XY从-100开始
boat-X2Y2始于-450
那是 350 的距离。
每步/每圈，船都移动10（Y + = 10）。
经过80步（取决于当前的窗口大小，目前为700），boat-XY离开屏幕，从位置710移回-100。
该测试为7 10 ，因为该测试是在Y位置> 大于700（窗口高度）时进行的。因此，您也可以在此运动中独占一筹。
boat-XY重新启动时，boat-X2Y2现在位于-450 + 810→360的位置。因此，距离为 460 。
在另外35个步骤中，boat-X2Y2到达底部，返回到-450。目前，boat-XY已前进了350步（从-100开始）到位置250，使距离 700 。
等等。随着窗口大小的变化，这种效果也会随之改变。
我认为这是一个非常有趣的效果。当然，这不是您想要的，但是它在船上融合了一些“发条随机性”。