Question

我有两个objectcs数组

const a = [
  {
    "categoryId": 1,
    "categoryName": "category 1",
    "id": 11
  },
  {
    "categoryId": 2,
    "teamName": "category 2",
    "id": 22
  }
]

const b = [
  {
    "categoryId": 2,
    "categoryName": "category 2",
    "id": 33
  },
  {
    "categoryId": 3,
    "categoryName": "category 3",
    "id": 44
  }
]

现在我想将它们合并在一起，最终结果应如下所示：

const result = [
  {
    "categoryId": 1,
    "categoryName": "category 1",
    "aId": 11,
    "bId" null: 
  },
  {
    "categoryId": 2,
    "categoryName": "category 2",
    "aId": 22,
    "bId" 33:
  },
  {
    "categoryId": 3,
    "categoryName": "category 3",
    "aId": null,
    "bId" 44:
  }
]

我看不到如何分配空值。

我已经使用Object.assign和“ ...”运算符对其进行了尝试，但没有得到想要的结果。

以相同的方式，我想根据ID的数组将ID重命名为新键。

让result = a.concat（b）会给我一个错误的结果

Answer 1

您可以使用contat()将数组合并在一起，然后使用reduce()通过其键删除重复的对象：

    const admin = [
      {
        "categoryId": 66,
        "categoryName": "category 66",
        "id": 204
      },
      {
        "categoryId": 149,
        "teamName": "category 149",
        "id": 178
      }
    ]

    const member = [
      {
        "categoryId": 66,
        "teamName": "category 66",
        "id": 271
      },
      {
        "categoryId": 68,
        "teamName": "category 68",
        "id": 264
      }
    ];
    
    const client = [
      {
        "categoryId": 66,
        "teamName": "category 66",
        "id": 271
      },
      {
        "categoryId": 155,
        "teamName": "no team",
        "id": 264
      }
    ];
    const merge = function(...params) {
        let mergeResult = [];
        params.map(elem => {mergeResult = mergeResult.concat(elem); });
        return mergeResult;
    }

    const result = Object.values(merge(member, admin, client).reduce((acc,cur)=>Object.assign(acc,{[cur.categoryId]:cur}),{}));

    console.log(result);

如果您需要更改重复的过滤器条件，只需在cur.categoryId函数中更改Object.assign()

Answer 2

您可以使用echo ls -l | sh # Passes the output of "echo ls -l" to the shell, #+ with the same result as a simple "ls -l"来获取唯一的ID，然后可以在其上进行映射，找到匹配的数据并以所需的格式构建对象：

Set

Answer 3

forEach循环可以使用，我们可以相应地分配值

const admin = [
    {
      "categoryId": 66,
      "categoryName": "category 66",
      "id": 204
    },
    {
      "categoryId": 149,
      "teamName": "category 149",
      "id": 178
    }
  ]
  
  const member = [
    {
      "categoryId": 66,
      "teamName": "category 66",
      "id": 271
    },
    {
      "categoryId": 68,
      "teamName": "category 68",
      "id": 264
    }
  ]
var arr=[];
  var k=admin.forEach((e)=>{
    var a=e.categoryId;
   if(e.teamName)
   {
e.categoryName=e.teamName;
delete e.teamName;
   }
   if(e.id)
e.adminid=e.id;
else
e.id=null
e.memberId=null;
delete e.id
var t=member.forEach((x)=>{
  if(x.categoryId==a)
  e.memberId=x.id;

})
arr.push(e);
  })
console.log(arr)

es6将两个数组与对象合并并累积数据

3 个答案: