Question

数组1：

array (size=1)
   0 => 
      object(stdClass)[93]
         public 'case' => string '12571' (length=5)
         public 'status' => string 'aktiv' (length=5)
         public 'id' => string '001345821' (length=9)
         public 'expires' => string '1392681600' (length=10)

数组2：

array (size=66)
   0 => 
     object(stdClass)[25]
       public 'id' => string '001345821' (length=9)
       public 'date' => int 1415602800
       public 'amount' => string '1069.31' (length=7)
   1 => 
     object(stdClass)[26]
       public 'id' => string '001345680' (length=9)
       public 'date' => int 1415602800
       public 'amount' => string '1035.00' (length=7)

我想在＆＃34; id＆＃34;上合并数组1和2字段，只保留数组1的匹配。

我想要的是什么：

array ()
   0 =>
     object(stdClass)
       public 'case' => string '1257' (length=5)
       public 'status' => string 'aktiv' (length=5)
       public 'id' => string '001345821' (length=9)
       public 'expires' => string '1392681600' (length=10)
       public 'date' => int 1415602800
       public 'amount' => string '1069.31' (length=7)

Answer 1

如果您的对象仅包含属性，则在这种情况下可以使用数组合并。当然，首先，只需使用一个循环。然后在循环下，让你的if检查那些共享相同ID的人，然后你需要将它们作为数组合并，然后再将它们重新设置为对象：

foreach($array2 as &$value2) {
    foreach($array1 as $value1) {
        if($value2->id == $value1->id) {
            $value2 = (object) array_merge((array) $value2, (array) $value1);
        }
    }
}

Sample Out

PHP：合并两个对象数组

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