Question

第一个阵列：

[ { B: 
     [ {
         name: '1-1-1',
        },
       { 
         name: '1-1-2',
      } ],
    name: '1-1', },
  { B: 
     [ { 
         name: '1-2-1',
          },
       { 
         name: '1-2-2',
         } ],

    name: '1-2',
 } ]

第二阵列：

[{ A: 
  [{ name: '1-1',
    B: 
     [{
        name: '1-1-1',
      },
      { 
        name: '1-1-2',
      }],
    },
   { name: '1-2',
     [{ 
       name: '1-2-1',
      },
      { 
        name: '1-2-2',
      }]
    }],
    name: '1',
}]

我希望最终输出是这样的：

     var finalArray = []
            _.each(firstArray, function(itemA) {
              _.each(secondArray, function(itemB) {
                if (itemB.name === itemA.name) {
                 itemA.B = itemB.B 
//Fails here but if i do something like itemA.sjdc = 'skdjn' it comes successfully
                }
              })
              finalArray.push(itemA)
            })

我尝试使用map和filter但是我使用了太多for循环遍历每个并构建最终结果。有没有更简单的方法呢？

我试过的代码：

command = r"adb shell screencap -p"
proc = subprocess.Popen(shlex.split(command),stdout=subprocess.PIPE)
out = proc.stdout.read(30000000)
img = cv2.imdecode(out,cv2.IMREAD_COLOR)
if img is not None:
    cv2.imshow("",img)
    cv2.waitKey(0)
    cv2.destroyWindow("")

Answer 1

使用第二个数组的相应项更新第一个数组要容易得多。 Map用于获取具有父名称的对象。

var one = [{ A: [{ name: '1-1' }, { name: '1-2' }], name: '1' }],
    two = [{ B: [{ name: '1-1-1' }, { name: '1-1-2', }], name: '1-1' }, { B: [{ name: '1-2-1' }, { name: '1-2-2', }], name: '1-2' }],
    map = new Map(two.map(o => [o.name, o.B]));

one.forEach(({ A }) => A.forEach(o => o.B = map.get(o.name)));
    
console.log(one);

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通过创建新的独立数组来完成。

var one = [{ A: [{ name: '1-1' }, { name: '1-2' }], name: '1' }],
    two = [{ B: [{ name: '1-1-1' }, { name: '1-1-2', }], name: '1-1' }, { B: [{ name: '1-2-1' }, { name: '1-2-2', }], name: '1-2' }],
    map = new Map(two.map(o => [o.name, o.B]));
    merged = one.map(o =>
        Object.assign({}, o, { A: o.A.map(p =>
            Object.assign({}, p, { B: map.get(p.name) })
        ) })
    );

console.log(merged);
console.log(one);
console.log(two);

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使用javascript合并两个对象数组

1 个答案: