Question

问题是我正在尝试编写代码，以便将我的.txt文件重新写入其自身更易于管理的版本中。该“程序”需要一次读取七行，然后将其作为一行写到另一个.txt文件中，然后重复此功能，直到遍历整个.txt文件为止。

我一直在Internet上查找并尝试过多种方法，但是以下代码甚至都无法与我所需要的最接近。

first_line = 7

def function():

    with open ('file_txt', 'r') as read_file1:

            line = [next(read_file1) for x in range(first_line)]

            with open ('file_txt_new', 'w') as write_file2:

                    write_file2.write(str(line))

输入文本文件如下：

Awakened Shrub
Small plant, unaligned
Hit Points:
10 (3d6) Armor Class:
9 Speed:
20 ft. Challenge Rating:
0 (10 XP)

预期结果：这些结果只是原始文本文件在一行中被重写。

示例1：这将写在新文本文档的第一行上。

Awakened Shrub, Small plant, unaligned, Hit Points: 10 (3d6) Armour Class: 9

示例2：这将写在新文本文档的第二行。

Baboon, Small beast, unaligned, Hit Points: 1 (1d4 - 1) Armour Class: 9

实际结果：

['Awakened Shrub\n', 'Small plant, unaligned\n', 'baboon\n', 'Small beast, unaligned\n',]

Answer 1

您的代码正在制作list，但是要执行您想要的操作，您需要将它们放回一个字符串中（str(line)不会这样做，因为那样会产生字符串list的表示形式；您需要str.join）：

first_line = 7

def function():
    # Open output file once up front (or you'll replace it for each new set of seven lines)
    with open('file_txt', 'r') as read_file1, open('file_txt_new', 'w') as write_file2:
        while True:
            # Get the lines, providing a default value to next in case you run out of lines
            lines = [next(read_file1, '') for x in range(first_line)]
            # Convert to a single string, and replace newlines with `, ` matching expected output
            newline = ''.join(lines).rstrip('\n').replace('\n', ', ')
            # Got nothing but empty lines, must have exhausted file, so we're done
            if not newline:
                break
            write_file2.write(newline + "\n")

注意：您可以使用itertools.islice来稍微简化/加快代码的速度，前提是允许导入模块，请替换：

            lines = [next(read_file1, '') for x in range(first_line)]

具有：

            lines = itertools.islice(read_file1, first_line)

Answer 2

我认为以下代码可以帮助您：

if(response.data.is_success){
    mainView.router.loadPage({url:'user-product.html', ignoreCache:true, 
    reload:true });

}

到达文件末尾时，将引发num_reads = 7 with open('data.txt') as read_file: with open('new_data.txt', 'w') as write_file: while (True): lines = [] try: # You should expect errors if the number of lines in the file are not a multiplication of num_reads for i in range(num_reads): lines.append(next(read_file)) # when the file finishes an exception occurs here #do sutff with the lines (exactly num_reads number of lines) processed = " ".join(list(map(lambda x: x.replace("\n", ''), lines))) write_file.write(processed + '\n') except StopIteration: # here we process the (possibly) insufficent last lines #do stuff with the lines (less that num_reads) processed = " ".join(list(map(lambda x: x.replace("\n", ''), lines))) write_file.write(processed + '\n') break错误并被StopIteration捕获，您可以在其中处理捕获到的可能不足的数据行并跳出except循环。在上面的代码中，我对完全捕获（num_reads = 7）和部分捕获都执行了相同的操作。处理部分仅附加行并删除换行符。当while像这样时：

data.txt

line1 line2 line3 line4 line5 line6 line7 line8 line9 line10会像这样：

new_data.txt

我将如何重新编写文件，使其变得更易于管理？

2 个答案: