我试图从字符串中提取具有相对路径('/folder/image.jpg', 'someimage.png')
而不是绝对路径(https://www.example.com/abc.jpg)
的图像,然后将所有图像压入某个数组。
当前数组:
["123.png", "abc.jpg", "xyz.jpg", "http://example.com/abc.jpg", "https://example.com/xyz.jpg", "popcorn.png"]
预期数组: ["123.png", "abc.jpg", "xyz.jpg", "popcorn.png"]
测试:https://codepen.io/Ashish9342/pen/qLwWYz?editors=0011
var content = 'Lorem ipsum dolor sit amet, consectetur <img style="height:10px" src="123.png"/> adipiscing elit. Praesent sed orci vitae nulla ultricies vehicula. Donec ex arcu, ultricies at nisl et, convallis lobortis nisl. Pellentesque aliquet luctus mollis. <img src="abc.jpg"/> Ut vehicula, lectus et iaculis molestie, est purus dignissim magna, sit amet tincidunt quam ante varius neque. Pellentesque quis ligula <img class="fantom" src="xyz.jpg"/> in risus efficitur ullamcorper. Vestibulum ante ipsum primis in faucibus orci luctus et ultrices posuere cubilia Curae; Duis porta, eros at sollicitudin viverra, nisl lectus dapibus erat, id rutrum augue augue sed lectus. <img src="http://example.com/abc.jpg"/> Nullam felis augue, placerat vel mattis et, viverra sit amet elit. Cras pulvinar iaculis massa, sed consectetur <img src="https://example.com/xyz.jpg"/> ligula luctus non. Donec vel augue mattis tellus rutrum ultricies et suscipit <img src="popcorn.png" alt="pop corn"/> erat.'
function getRelativePathImages(content) {
if (content && content.search('<img')) {
const urls = [];
let m;
const rex = /<img[^>]+src="([^">]+)/g;
// const rex = /<img[^>]+src="([^http">]+)/g;
while (m = rex.exec(content)) {
if (urls.indexOf(m[1]) < 0) {
urls.push(m[1]);
}
}
console.log(urls);
}
}
getRelativePathImages(content);
答案 0 :(得分:1)
只需在'config': {
'gceClusterConfig': {
"metadata": {
"bigquery-connector-version": "0.12.1",
"gcs-connector-version": "1.8.1"
}
}
}
之后的正则表达式(?!http)
中使用负向查找,这将拒绝以src="
开头的所有网址,并将正则表达式更改为
http
/<img[^>]+src="(?!http)([^">]+)/g
答案 1 :(得分:0)
如果不需要的路径以http
开头,则不需要正则表达式。只需使用startsWith
方法:
s = "http://example.com/abc.jpg";
if(!s.startsWith("http")){
// add s to you array of URLs
}