接下来是代码:
import urllib
url=r'http://yann.lecun.com/exdb/mnist\train-images-idx3-ubyte.gz'
urllib.request.urlretrieve(url,'demo.zip')
接下来是错误:
HTTPError Traceback (most recent call last)
<ipython-input-3-a702ad6c8455> in <module>()
1 import urllib
2 url=r'http://yann.lecun.com/exdb/mnist\train-images-idx3-ubyte.gz'
----> 3 urllib.request.urlretrieve(url,'demo.zip')
c:\program files (x86)\microsoft visual studio\shared\python36_64\lib\urllib\request.py in urlretrieve(url, filename, reporthook, data)
246 url_type, path = splittype(url)
247
--> 248 with contextlib.closing(urlopen(url, data)) as fp:
249 headers = fp.info()
250
221 else:
222 opener = _opener
--> 223 return opener.open(url, data, timeout)
224
225 def install_opener(opener):
530 for processor in self.process_response.get(protocol, []):
531 meth = getattr(processor, meth_name)
--> 532 response = meth(req, response)
533
534 return response
640 if not (200 <= code < 300):
641 response = self.parent.error(
--> 642 'http', request, response, code, msg, hdrs)
643
644 return response
c:\program files (x86)\microsoft visual studio\shared\python36_64\lib\urllib\request.py in error(self, proto, *args)
562 http_err = 0
563 args = (dict, proto, meth_name) + args
--> 564 result = self._call_chain(*args)
565 if result:
566 return result
c:\program files (x86)\microsoft visual studio\shared\python36_64\lib\urllib\request.py in _call_chain(self, chain, kind, meth_name, *args)
502 for handler in handlers:
503 func = getattr(handler, meth_name)
--> 504 result = func(*args)
505 if result is not None:
506 return result
HTTPError: HTTP Error 404: Not Found
如此糟糕的请求,你能帮我吗.. 此错误不是针对代码的。我想到了我的浏览器或urllib模块错误。
答案 0 :(得分:0)
网址应为:
http://yann.lecun.com/exdb/mnist/train-images-idx3-ubyte.gz
mnist后有一个反斜杠,导致将其解释为制表符。